Given a string str, the task is to make the string empty with the given operation. In a single operation, you can pick some characters of the string (each of the picked characters should have the same frequency) and remove them from the string. Print the total operations required to make the string empty.
Input: str = “aabbccc”
In one operation, characters ‘a’ and ‘b’ can be removed since both have the same frequency.
Second operation can remove character ‘c’ having frequency 3.
Total 2 operations are required.
Input: str = “geeksforgeeks”
Approach: Find unique frequencies of the characters of the string. Total count of unique frequencies will be the number of operations required to make the string empty.
For str = “aaabbbcccc”, unique frequencies are 3 and 4. Total count of unique frequencies is 2.
HashMap can be used to store the characters and their frequencies then HashSet can be used to find the count of unique frequencies which is the number of operations required.
Below is the implementation of the above approach:
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- Count of operations to make a binary string"ab" free
- Minimum swaps required to make a binary string alternating
- String slicing in Python to check if a string can become empty by recursive deletion
- Count the number of carry operations required to add two numbers
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