numpy.setxor1d() function in Python
Last Updated :
17 May, 2020
numpy.setxor1d()
function find the set exclusive-or of two arrays and return the sorted, unique values that are in only one (not both) of the input arrays.
Syntax : numpy.setxor1d(arr1, arr2, assume_unique = False)
Parameters :
arr1, arr2 : [array_like] Input arrays.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
Return : [ndarray] Sorted 1D array of unique values that are in only one of the input arrays.
Code #1 :
import numpy as geek
arr1 = [ 1 , 2 , 3 , 4 ]
arr2 = [ 2 , 4 , 6 , 8 ]
gfg = geek.setxor1d(arr1, arr2)
print (gfg)
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Output :
[1 3 6 8]
Code #2 :
import numpy as geek
arr1 = [ 1 , 2 , 3 , 4 , 5 ]
arr2 = [ - 2 , - 1 , 0 , 1 , 2 ]
gfg = geek.setxor1d(arr1, arr2)
print (gfg)
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Output :
[-2 -1 0 3 4 5]
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