numpy.polyint() in Python
Last Updated :
29 Nov, 2018
numpy.polyint(p, m)
: Evaluates the anti – derivative of a polynomial with the specified order.
m antiderivative ‘P’ of polynomial ‘p’ satisfies
Parameters :
p : [array_like or poly1D] polynomial coefficients are given in decreasing order of powers. If the second parameter (root) is set to True then array values are the roots of the polynomial equation. For example, poly1d(3, 2, 6) = 3x2 + 2x + 6
m : [int, optional] Order of anti-derivative. Default is 1.
Return: Anti-Derivative of the polynomial.
Code #1:
import numpy as np
p1 = np.poly1d([ 1 , 2 ])
p2 = np.poly1d([ 4 , 9 , 5 , 4 ])
print ( "P1 : " , p1)
print ( "\n p2 : \n" , p2)
print ( "\n\np1 at x = 2 : " , p1( 2 ))
print ( "p2 at x = 2 : " , p2( 2 ))
a = np.polyint(p1, 1 )
b = np.polyint(p2, 1 )
print ( "\n\nUsing polyint" )
print ( "p1 anti-derivative of order = 1 : \n" , a)
print ( "p2 anti-derivative of order = 1 : \n" , b)
a = np.polyint(p1, 2 )
b = np.polyint(p2, 2 )
print ( "\n\nUsing polyint" )
print ( "p1 anti-derivative of order = 2 : \n" , a)
print ( "p2 anti-derivative of order = 2 : \n" , b)
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Output :
P1 :
1 x + 2
p2 :
3 2
4 x + 9 x + 5 x + 4
p1 at x = 2 : 4
p2 at x = 2 : 82
Using polyint
p1 anti-derivative of order = 1 :
2
0.5 x + 2 x
p2 anti-derivative of order = 1 :
4 3 2
1 x + 3 x + 2.5 x + 4 x
Code #2:
import numpy as np
p1 = np.poly1d([ 1 , 2 ])
p2 = np.poly1d([ 4 , 9 , 5 , 4 ])
a = np.polyint(p1, 2 )
b = np.polyint(p2, 2 )
print ( "\n\nUsing polyint" )
print ( "p1 anti-derivative of order = 2 : \n" , a)
print ( "p2 anti-derivative of order = 2 : \n" , b)
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Output :
Using polyint
p1 anti-derivative of order = 2 :
3 2
0.1667 x + 1 x
p2 anti-derivative of order = 2 :
5 4 3 2
0.2 x + 0.75 x + 0.8333 x + 2 x
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