numpy.outer()
function compute the outer product of two vectors.
Syntax : numpy.outer(a, b, out = None)
Parameters :
a : [array_like] First input vector. Input is flattened if not already 1-dimensional.
b : [array_like] Second input vector. Input is flattened if not already 1-dimensional.
out : [ndarray, optional] A location where the result is stored.
Return : [ndarray] Returns the outer product of two vectors. out[i, j] = a[i] * b[j]
Code #1 :
import numpy as geek
a = geek.ones( 4 )
b = geek.linspace( - 1 , 2 , 4 )
gfg = geek.outer(a, b)
print (gfg)
|
Output :
[[-1. 0. 1. 2.]
[-1. 0. 1. 2.]
[-1. 0. 1. 2.]
[-1. 0. 1. 2.]]
Code #2 :
import numpy as geek
a = geek.ones( 5 )
b = geek.linspace( - 2 , 2 , 5 )
gfg = geek.outer(a, b)
print (gfg)
|
Output :
[[-2. -1. 0. 1. 2.]
[-2. -1. 0. 1. 2.]
[-2. -1. 0. 1. 2.]
[-2. -1. 0. 1. 2.]
[-2. -1. 0. 1. 2.]]