Numpy MaskedArray.default_fill_value() function | Python
Last Updated :
29 Oct, 2019
numpy.MaskedArray.default_fill_value()
function is used to return the default fill value for the argument object.The default filling value depends on the datatype of the input array or the type of the input scalar.If datatype is bool then default filling value is True, for int it is 999999, 1.e20 for float, for complex it is 1.e20+0.j, ‘?’ for object and ‘N/A’ for string.
Syntax : numpy.ma.default_fill_value(obj)
Parameters:
obj :[ ndarray, dtype or scalar ] The array data-type or scalar for which the default fill value is returned.
Return : [ scalar ] The default fill value.
Code #1 :
import numpy as geek
import numpy.ma as ma
in_arr = geek.array([[ 1 , 2 ], [ 3 , - 1 ], [ 5 , - 3 ]])
print ( "Input array : " , in_arr)
mask_arr = ma.masked_array(in_arr,
mask = [[ 1 , 0 ], [ 1 , 0 ], [ 0 , 0 ]])
print ( "Masked array : " , mask_arr)
out_val = ma.default_fill_value(mask_arr)
print ( "Default filled value : " , out_val)
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Output:
Input array : [[ 1 2]
[ 3 -1]
[ 5 -3]]
Masked array : [[-- 2]
[-- -1]
[5 -3]]
Default filled value : 999999
Code #2 :
import numpy as geek
import numpy.ma as ma
in_arr = geek.array([[ 1 + 2j , 2 + 3j ],
[ 3 - 2j , - 1 + 2j ],
[ 5 - 4j , - 3 - 3j ]])
print ( "Input array : " , in_arr)
mask_arr = ma.masked_array(in_arr,
mask = [[ 1 , 0 ], [ 1 , 0 ], [ 0 , 0 ]])
print ( "Masked array : " , mask_arr)
out_val = ma.default_fill_value(mask_arr)
print ( "Default filled value : " , out_val)
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Output:
Input array : [[ 1.+2.j 2.+3.j]
[ 3.-2.j -1.+2.j]
[ 5.-4.j -3.-3.j]]
Masked array : [[-- (2+3j)]
[-- (-1+2j)]
[(5-4j) (-3-3j)]]
Default filled value : (1e+20+0j)
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