numpy.less_equal() in Python
The numpy.less_equal() function checks whether x1 is <= x2 or not.
Syntax :
numpy.less_equal(x1, x2[, out])
Parameters :
x1, x2 : [array_like]Input arrays. If x1.shape != x2.shape, they must be
broadcastable to a common shape
out : [ndarray, boolean]Array of bools, or a single bool if x1 and x2 are scalars.
Return :
Boolean array indicating results, whether x1 is lesser than x2 or not.
Code 1 :
import numpy as geek
a = geek.less_equal([ 8. , 2. ], [ 5. , 3. ])
print ( "less_equal() : \n" , a, "\n" )
b = geek.less_equal([ 2 , 2 ], [[ 1 , 3 ],[ 1 , 4 ]])
print ( "less_equal() : \n" , b, "\n" )
a = geek.array([ 4 , 3 ])
b = geek.array([ 6 , 2 ])
print ( "Is a less_equal than b : " , a < = b)
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Output :
less_equal() :
[False True]
less_equal() :
[[False True]
[False True]]
Is a less_equaler than b : [ True False]
Code 2 :
import numpy as geek
a = geek.array([ 100j , 7 ])
b = geek.array([ 1 , 2 ])
print ( "Comparing complex with int : " , a < = b)
d = geek.less_equal(a, b)
print ( "\n Comparing complex with int .less_equal() : " , d)
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Output :
Comparing complex with int : [ True False]
Comparing complex with int .less_equal() : [ True False]
Code 3 :
import numpy as geek
a = geek.array([ 1.1 , 1 ])
b = geek.array([ 1 , 2 ])
print ( "Comparing float with int : " , a < = b)
d = geek.less_equal(a, b)
print ( "\n Comparing float with int using .less_equal() : " , d)
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Output :
Comparing float with int : [False True]
Comparing float with int using .less_equal() : [False True]
Note :
These codes won’t run on online-ID. Please run them on your systems to explore the working.
Last Updated :
08 Mar, 2024
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