numpy.isinf() in Python
Last Updated :
08 Mar, 2024
The numpy.isinf() function tests element-wise whether it is +ve or -ve infinity or not return the result as a boolean array.
Syntax: numpy.isinf(array [, out])
Parameters :
array : [array_like]Input array or object whose
elements, we need to test for infinity
out : [ndarray, optional]Output array placed
with result. Its type is preserved and
it must be of the right shape to hold
the output.
Return :
boolean array containing the result. For scalar
input, the result is a new boolean with value
True if the input is positive or negative infinity;
otherwise the value is False. For array input, the
result is a boolean array with the same shape as
the input and the values are True where the
corresponding element of the input is positive
or negative infinity; elsewhere the values are False.
Code 1 :
Python
import numpy as geek
print ( "Finite : " , geek.isinf( 1 ), "\n" )
print ( "Finite : " , geek.isinf( 0 ), "\n" )
print ( "Finite : " , geek.isinf(geek.nan), "\n" )
print ( "Finite : " , geek.isinf(geek.inf), "\n" )
print ( "Finite : " , geek.isinf(geek.NINF), "\n" )
x = geek.array([ - geek.inf, 0. , geek.inf])
y = geek.array([ 2 , 2 , 2 ])
print ( "Checking for infinity : " , geek.isinf(x, y))
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Output :
Finite : False
Finite : False
Finite : False
Finite : True
Finite : True
Checking for infinity : [1 0 1]
Code 2 :
Python
import numpy as geek
b = geek.arange( 8 ).reshape( 2 , 4 )
print ( "\n" ,b)
print ( "\nIs Infinity : \n" , geek.isinf(b))
b = [[geek.inf],
[geek.NINF]]
print ( "\nIs Infinity : \n" , geek.isinf(b))
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Output :
[[0 1 2 3]
[4 5 6 7]]
Is Infinity :
[[False False False False]
[False False False False]]
Is Infinity :
[[ True]
[ True]]
Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
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