numpy.isfinite() in Python
Last Updated :
08 Mar, 2024
The numpy.isfinite() function tests element-wise whether it is finite or not(not infinity or not Not a Number) and return the result as a boolean array. Syntax :
numpy.isfinite(array [, out])
Parameters :
array : [array_like]Input array or object whose elements,
we need to test for infinity
out : [ndarray, optional]Output array placed with result.
Its type is preserved and it must be of the right
shape to hold the output.
Return :
boolean array containing the result
Code 1 :
Python
import numpy as geek
print ( "Finite : " , geek.isfinite( 1 ), "\n" )
print ( "Finite : " , geek.isfinite( 0 ), "\n" )
print ( "Finite : " , geek.isfinite(geek.nan), "\n" )
print ( "Finite : " , geek.isfinite(geek.inf), "\n" )
print ( "Finite : " , geek.isfinite(geek.NINF), "\n" )
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Output :
Finite : True
Finite : True
Finite : False
Finite : False
Finite : False
Code 2 :
Python
import numpy as geek
b = geek.arange( 20 ).reshape( 5 , 4 )
print ( "\n" ,b)
print ( "\nIs Finite : \n" , geek.isfinite(b))
b = [[ 1j ],
[geek.inf]]
print ( "\nIs Finite : \n" , geek.isfinite(b))
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Output :
[[ 0 1 2 3]
[ 4 5 6 7]
[ 8 9 10 11]
[12 13 14 15]
[16 17 18 19]]
Is Finite :
[[ True True True True]
[ True True True True]
[ True True True True]
[ True True True True]
[ True True True True]]
Is Finite :
[[ True]
[False]]
Note : These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
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