The numpy.iscomplex() function tests element-wise whether it is a complex number or not(not infinity or not Not a Number) and returns the result as a boolean array.
Syntax :
numpy.iscomplex(array)
Parameters :
array : [array_like] Input array whose element we want to test
Return :
boolean array containing the result
Code 1 :
# Python Program illustrating # numpy.iscomplex() method import numpy as geek print ( "Is Complex : " , geek.iscomplex([ 1 + 1j , 1 + 0j ]), "\n" ) print ( "Is Complex : " , geek.iscomplex([ 0 + 1j , 0 ]), "\n" ) |
Output :
Is Complex : [ True False] Is Complex : [ True False]
Code 2 :
# Python Program illustrating # numpy.iscomplex() method import numpy as geek # Returns True/False value for each element a = geek.arange( 20 ).reshape( 5 , 4 ) print ( "Is complex : \n" , geek.iscomplex(a)) # Returns True/False value as ans # because we have mentioned dtpe in the beginning b = geek.arange( 20 ).reshape( 5 , 4 ).dtype = complex print ( "\n" ,b) print ( "\nIs complex : " , geek.iscomplex(b)) b = [[ 1j ], [ 3 ]] print ( "\nIs complex : \n" , geek.iscomplex(b)) |
Output :
Is complex : [[False False False False] [False False False False] [False False False False] [False False False False] [False False False False]] Is complex : False Is complex : [[ True] [False]]
References :
https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.isfinite.html
Note :
These codes wonβt run on online-ID. Please run them on your systems to explore the working.
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