numpy.intersect1d() function in Python
Last Updated :
17 May, 2020
numpy.intersect1d()
function find the intersection of two arrays and return the sorted, unique values that are in both of the input arrays.
Syntax: numpy.intersect1d(arr1, arr2, assume_unique = False, return_indices = False)
Parameters :
arr1, arr2 : [array_like] Input arrays.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
return_indices : [bool] If True, the indices which correspond to the intersection of the two arrays are returned. The first instance of a value is used if there are multiple. Default is False.
Return : [ndarray] Sorted 1D array of common and unique elements.
Code #1 :
import numpy as geek
arr1 = geek.array([ 1 , 1 , 2 , 3 , 4 ])
arr2 = geek.array([ 2 , 1 , 4 , 6 ])
gfg = geek.intersect1d(arr1, arr2)
print (gfg)
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Output :
[1 2 4]
Code #2 :
import numpy as geek
arr1 = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ]
arr2 = [ 1 , 3 , 5 , 7 , 9 ]
gfg = geek.intersect1d(arr1, arr2)
print (gfg)
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Output :
[1 3 5 7 9]
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