numpy.array_equal() in Python
Last Updated :
29 Nov, 2018
numpy.array_equal(arr1, arr2) : This logical function that checks if two arrays have the same shape and elements.
Parameters :
arr1 : [array_like]Input array or object whose elements, we need to test.
arr2 : [array_like]Input array or object whose elements, we need to test.
Return :
True, if both arrays have same shape and value; otherwise False
Code : Explaining Working
import numpy as np
arr1 = np.arange( 4 )
arr2 = [ 7 , 4 , 6 , 7 ]
print ( "arr1 : " , arr1)
print ( "arr2 : " , arr2)
print ( "\nResult : " , np.array_equal(arr1, arr2))
arr1 = np.arange( 4 )
arr2 = np.arange( 4 )
print ( "\n\narr1 : " , arr1)
print ( "arr2 : " , arr2)
print ( "\nResult : " , np.array_equal(arr1, arr2))
arr1 = np.arange( 4 )
arr2 = np.arange( 5 )
print ( "\n\narr1 : " , arr1)
print ( "arr2 : " , arr2)
print ( "\nResult : " , np.array_equal(arr1, arr2))
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Output :
arr1 : [0 1 2 3]
arr2 : [7, 4, 6, 7]
Result : False
arr1 : [0 1 2 3]
arr2 : [0 1 2 3]
Result : True
arr1 : [0 1 2 3]
arr2 : [0 1 2 3 4]
Result : False
References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.array_equal.html
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