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NumPy – 3D matrix multiplication

  • Difficulty Level : Easy
  • Last Updated : 12 Nov, 2020

A 3D matrix is nothing but a collection (or a stack) of many 2D matrices, just like how a 2D matrix is a collection/stack of many 1D vectors. So, matrix multiplication of 3D matrices involves multiple multiplications of 2D matrices, which eventually boils down to a dot product between their row/column vectors.

Let us consider an example matrix A of shape (3,3,2) multiplied with another 3D matrix B of shape (3,2,4).

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Python






import numpy as np
  
np.random.seed(42)
  
A = np.random.randint(0, 10, size=(3, 3, 2))
B = np.random.randint(0, 10, size=(3, 2, 4))
  
print("A:\n{}, shape={}\nB:\n{}, shape={}".format(
  A, A.shape, B, B.shape))

OUTPUT:

The first matrix is a stack of three 2D matrices each of shape (3,2), and the second matrix is a stack of 3 2D matrices, each of shape (2,4).

The matrix multiplication between these two will involve three multiplications between corresponding 2D matrices of A and B having shapes (3,2) and (2,4) respectively. Specifically, the first multiplication will be between A[0] and B[0], the second multiplication will be between A[1] and B[1], and finally, the third multiplication will be between A[2] and B[2]. The result of each individual multiplication of 2D matrices will be of shape (3,4). Hence, the final product of the two 3D matrices will be a matrix of shape (3,3,4).

Let’s realize this using code.

Python




C = np.matmul(A, B)
  
print("Product C:\n{}, shape={}".format(C, C.shape))

Output:




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