Given an integer n, we need to find the number of positive integers whose factorial ends with n zeros.
Input : n = 1 Output : 5 6 7 8 9 Explanation: Here, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880. Input : n = 2 Output : 10 11 12 13 14
Prerequisite : Trailing zeros in factorial.
Naive approach:We can just iterate through the range of integers and find the number of trailing zeros of all the numbers and print the numbers with n trailing zeros.
Efficient Approach:In this approach we use binary search. Use binary search for all the numbers in the range and get the first number with n trailing zeros. Find all the numbers with m trailing zeros after that number.
10 11 12 13 14
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