Given two integers(less than 2^31) A and B. The task is to find the number of bits that are different in their binary representation.
Input : A = 12, B = 15 Output : Number of different bits : 2 Explanation: The binary representation of 12 is 1100 and 15 is 1111. So, the number of different bits are 2. Input : A = 3, B = 16 Output : Number of different bits : 3
- Run a loop from ‘0’ to ’31’ and right shift the bits of A and B by ‘i’ places, then check whether the bit at the ‘0th’ position is different.
- If the bit is different then increase the count.
- As the numbers are less than 2^31, we only have to run the loop ’32’ times i.e. from ‘0’ to ’31’.
- We can get the 1st bit if we bitwise AND the number by 1.
- At the end of the loop display the count.
Below is the implementation of the above approach:
Number of different bits : 2
- Prime Number of Set Bits in Binary Representation | Set 1
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- Count of total bits toggled/flipped in binary representation of 0 to N
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- Check if the binary representation of a number has equal number of 0s and 1s in blocks
- Largest number with binary representation is m 1's and m-1 0's
- Binary representation of previous number
- Next greater number than N with exactly one bit different in binary representation of N
- Sum of digits with even number of 1's in their binary representation
- Number of leading zeros in binary representation of a given number
- Check if binary representation of a number is palindrome
- Find the n-th number whose binary representation is a palindrome
- Occurrences of a pattern in binary representation of a number
- Number of integers with odd number of set bits
- Check if actual binary representation of a number is palindrome
- Check if binary representation of a given number and its complement are anagram
- C program to count zeros and ones in binary representation of a number
- Find the number obtained after concatenation of binary representation of M and N
- Sum of decimal equivalent of all possible pairs of Binary representation of a Number
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