Number Divisibility Number Divisibility Please wait while the activity loads. If this activity does not load, try refreshing your browser. Also, this page requires javascript. Please visit using a browser with javascript enabled. If loading fails, click here to try again Question 1 There is bag of lots of integers from 1 to 10000, but you can only pick the numbers that are of 3-digit and also divisible by 3. What maximum sum of numbers you can pick. 165150 1600843 168132420 165322501 Arithmetic Aptitude 2 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 1-Explanation: All 3 digit numbers divisible by 3 are : 102, 105, 108, 111, ..., 999. This is an A.P. with first element \'a\' as 102 and difference \'d\' as 3. Let it contains n terms. Then, 102 + (n - 1) x 3 = 999 102 + 3n-3 = 999 3n = 900 or n = 300 Sum of AP = n/2 [2*a + (n-1)*d] Required sum = 300/2[2*102 + 299*3] = 165150. Question 2Which of Following is not divisible from 4 ?546702556824367312467536Arithmetic Aptitude 2 Number Divisibility Discuss itQuestion 2-Explanation: If last 2 digits are divisible by 4, then number is also divisible by 4. In case of 546702 last 2 digits are 02 (x) In case of 556824 last 2 digits are 24 (/) In case of 367312 last 2 digits are 12 (/) In case of 467536 last 2 digits are 36 (/) Question 3What should be the value of * in 985*865, if number is divisible by 9?6540Arithmetic Aptitude 2 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 3-Explanation: If a number is divisible by 9, the sum of digits is also divisible by 9 9 + 8 + 5 + * + 8 + 6 + 5 = 9x 41 + * = 9x Nearest value of 9x must be 45 41 + * = 45 * = 4Question 4The least perfect square, which is divisible by each of 15, 20 and 36 is: 12008001000900Arithmetic Aptitude 2 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 4-Explanation: LCM of 15, 20 and 36 is 180 Now 180 = 3 x 3 x 2 x 2 x 5 To make it perfect square, it must be multiplied from 5. So required no. = 32 x 22 x 52 = 900Question 5 Raghav has got a bag of numbers from 1 to 500, however he want to remove the numbers those are multiple of 9. How many total numbers will be removed? 44 55 50 52 Arithmetic Aptitude 4 Number Divisibility Discuss itQuestion 5-Explanation: The required numbers are 9, 18, 27, 36, 45……450, 459, 468, 477, 486, 495 This is an A.P. with a = 9 and d = 9 Let it has n terms. Then Tn = 495 = 9 + (n-1) x9 ∴ 495 = 9 + 9n - 9 ∴ 9n = 495 ∴ n = 55Question 6 Which digits should come in place of * and # if the number 4675*2# is divisible by both 5 & 8? 4, 0 4, 5 1, 0 8, 0 Arithmetic Aptitude 6 Number Divisibility Discuss itQuestion 6-Explanation: Since the given number is divisible by 5, 0 or 5 must come in place of $. But a number ending with 5 is never divisible with 8 because a divisible number must be even. Therefore 0 will replace $. If the number is divisible by 8, the number formed by last three digits must be divisible by 8. The number *20 must be divisible by 8. Among all 4 options, only placing 1 in place of * makes it divisible by 8. Question 7What least number must be added to 4000 to obtain a number exactly divisible by 17?12141513Arithmetic Aptitude 6 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 7-Explanation: Let us divide 4000 by 17. 17) 4000 (235 34 …. 60 51 ….. 90 85 ….. 5 We get 5 as remainder. Number to be added = 17-5 = 12Question 8 Gaurav is having 5000 chocolates and he decides to distribute these among his 23 friends. To make sure that every friend gets equal number of chocolates, he decides to eat x number of chocolates. What can be the minimum value of x? 10 2 7 9 Arithmetic Aptitude 6 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 8-Explanation: Let us divide 5000 by 23. 23) 5000 (217 46 …. 40 23 …. 170 161 ….. 9 We get 9 as remainder. Therefore required number to be subtracted = 9Question 9 X is a positive 4 digit number. Find the largest possible value of X, such that on dividing with 5, 6, 7 it gives the remainder zero. 9980 9870 9540 9640 Arithmetic Aptitude 6 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 9-Explanation: The required number must be divisible by L.C.M. of 5,6 and 7. L.C.M. of 5, 6 and 7 = 5 x 6 x 7 = 210 Let us divide 9999 by 210. 210) 9999 (47 840 ---- 1599 1470 ---- 129 Required number = 9999 – 129 = 9870Question 1034. What should be the next number in below series? 3, 8, 15, 24, 35…….. 44474849Arithmetic Aptitude 6 Number Divisibility 50 Aptitude & Reasoning MCQs with Answers Discuss itQuestion 10-Explanation: Pattern is (22- 1), (32- – 1), (42- – 1), (52- – 1), .... Next number will be = 72- – 1 = 49 – 1 = 48 12 There are 16 questions to complete. You have completed questions question Your accuracy is Correct Wrong Partial-Credit You have not finished your quiz. If you leave this page, your progress will be lost. Correct Answer You Selected Not Attempted Final Score on Quiz Attempted Questions Correct Attempted Questions Wrong Questions Not Attempted Total Questions on Quiz Question Details Results Date Score Hint Time allowed minutes seconds Time used Answer Choice(s) Selected Question Text Need more practice! Keep trying! Not bad! Good work! Perfect! Last Updated : 27 Sep, 2023 Share your thoughts in the comments Add Your Comment Please Login to comment...