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nth Roots

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Real numbers are the numbers that include both rational and irrational numbers. Rational numbers such as integers (-2, 0, 1), fractions(1/2, 2.5), and irrational numbers such as √3, π(22/7), etc., are all real numbers. The definition of the nth root of a real number can be stated as:

For any two real numbers a and b, and any positive integer n, if an = b, then a is an nth root of b. 

For Example:

34 = 81

Where,

a = 3, b = 81, and n = 4

That means that 3 is the fourth root of 81.

How to write nth Roots?

\sqrt[n]{} indicates an nth root. 

For Example:

\sqrt[n]{144}

Where,

144 = Radicand,

√ = Radical Sign, and

n = Index

That means that we are taking the nth root of 144. One can take any value of n, like n = 2, 3, 5, etc. We will be taking that root of 100.

Principal Root

Some numbers have more than one real nth root. For example, 36 has two roots, one is +6 and another is -6. In this case, the non-negative root is called the principal root

When no index is given the radical sign indicates the principal root. For example, if we take\sqrt{36} then we are talking about its principal root which is 6. 

Examples

Example 1: If n = 5 and b = 32  then a = ?

Solution:

Given: a5 = 32

=> a=\sqrt[5]{32}

2 . 2 . 2 . 2 . 2 = 32 

Since, 2 is the fifth root of 32

Therefore, a = 2

Example 2: n = 6 and b = 4096 then a = ?

Solution:

Given: a6 = 4096

=> a=\sqrt[6]{4096}

To find the value of a, we will check which integer value is the sixth root of 4096

2 . 2 . 2 . 2 . 2 . 2 = 64 

3 . 3 . 3 . 3 . 3 . 3 = 729 

4 . 4 . 4 . 4 . 4 . 4 = 4096 

Since, 4 is the sixth root of 4096 

Therefore, a = 4

Example 3: If a = 18, b = 2, n  = 2, and c= ( \sqrt[n]{a}\  * \sqrt[n]{b}) then find the value of c?

Solution:

Given: c = ( \sqrt[n]{a}\ * \sqrt[n]{b})

SInce the index value is same then the radicand is multiplied

\\ c=( \sqrt[2]{18} *  \sqrt[2]{2})\\ c= \sqrt[2]{36}

Since, 6 is the square root of 36 (62 = 36) 

Therefore, c = 6

Example 4: If a = 5, b = 15, n = 3 and c = ( \frac{\sqrt[n]{a}}{\sqrt[n]{b}}) then find the value of c?

Solution:

Given: c = ( \frac{\sqrt[n]{a}}{\sqrt[n]{b}})

SInce the index value is same then the radicand are divided

\\ c = \sqrt[n]{\frac{a}{b}} \\ c = \sqrt[3]{\frac{5}{15}}\\ c = \sqrt[3]{\frac{1}{3}}\\ c = \frac{1}{\sqrt[3]{3}}

Example 5: Solve the following: c = \sqrt[3]{1} +\sqrt[3]{ 8}+\sqrt[3]{27}+\sqrt[3]{64}

Solution:

Given: c = \sqrt[3]{1} +\sqrt[3]{ 8}+\sqrt[3]{27}+\sqrt[3]{64}\\ c= \sqrt[3]{1^3} +\sqrt[3]{2^3}+\sqrt[3]{3^3}+\sqrt[3]{4^3}

1 . 1 . 1 = 1, 1 is the cube root of 1

2 . 2 . 2 = 8, 2 is the cube root of 8

3 . 3 . 3 = 27, 3 is the cube root of 27

4 . 4 . 4 = 64, 4 is the cube root of 64

c = 1 + 2 + 3 + 4 

c = 10


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Last Updated : 19 Jan, 2021
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