Node.js stats.isFile() Method from fs.Stats Class
Last Updated :
25 Jun, 2020
The stats.isFile() method is an inbuilt application programming interface of the fs.Stats class which is used to check whether fs.Stats object describes a file or not.
Syntax:
stats.isFile();
Parameters: This method does not accept any parameters.
Return Value: This method returns a boolean value, which is true if fs.Stats object describes a file, false otherwise.
Below examples illustrate the use of stats.isFile() method in Node.js:
Example 1:
const fs = require( 'fs' );
fs.stat( './filename.txt' , (err, stats) => {
if (err) throw err;
console.log(stats.isFile());
});
fs.stat( './filename.txt' , (err, stats) => {
if (err) throw err;
if (stats.isFile()) {
console.log( "fs.Stats describes a file" );
} else {
console.log( "fs.Stats does not describe a file" );
}
});
|
Output:
true
fs.Stats describes a file
Example 2:
const fs = require( 'fs' );
fs.stat( './' , (err, stats) => {
if (err) throw err;
console.log(stats.isFile());
});
fs.stat( './' , (err, stats) => {
if (err) throw err;
if (stats.isFile()) {
console.log( "fs.Stats describes a file" );
} else {
console.log( "fs.Stats does not describe a file" );
}
});
|
Output:
false
fs.Stats does not describe a file
Note: The above program will compile and run by using the node filename.js
command and use the file_path correctly.
Reference: https://nodejs.org/api/fs.html#fs_stats_isfile
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