No. of vowels and consonants in a given string in PL/SQL

Last Updated : 05 Jul, 2018

In PL/SQL code groups of commands are arranged within a block. A block group related declarations or statements. In declare part, we declare variables and between begin and end part, we perform the operations.

Given a string and the task is to find the number of vowels and consonants present in the string.
Examples:

Input: str = 'Ramesh'
Output: Vowels = 2, Consonants = 4

Input: str = 'Ramesh is a Geek'
Output: Vowels = 6, Consonants = 7

Approach is to consider a character one by one and maintain a separate count for both vowels and consonants.

Below is the required implementation:

DECLARE 
    -- Here variable V is varchar datatype   
    -- and  flag variable is number datatype    
    -- variable c is char datatype .   
    v              VARCHAR2(400) := 'Ramesh is a Geek';  
    noofvowels     NUMBER := 0;  
    noofconsonants NUMBER := 0;  
    C              CHAR;  
BEGIN 
    FOR i IN 1..Length(v) LOOP  
        c := Substr(v, i, 1);  
  
        -- Check if the current character is vowel  
        IF c IN ( 'A', 'E', 'I', 'O', 'U' )  
            OR c IN ( 'a', 'e', 'i', 'o', 'u' ) THEN 
          noofvowels := noofvowels + 1;  
  
        -- Else current character is a consonant except space  
        ELSE 
          IF c NOT IN ( ' ' ) THEN 
            noofconsonants := noofconsonants + 1;  
          END IF;  
        END IF;  
    END LOOP;  
  
    dbms_output.Put_line('No. of Vowels: ' 
                         || noofvowels);  
  
    dbms_output.Put_line('No. of Consonants: ' 
                         || noofconsonants);  
END;  
-- Program End   

Output :

No. of Vowels: 6
No. of Consonants: 7

My Personal Notes

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