A neon number is a number where the sum of digits of square of the number is equal to the number. The task is to check and print neon numbers in a range.
Examples:
Input : 9 Output : Neon Number Explanation: square is 9*9 = 81 and sum of the digits of the square is 9. Input :12 Output : Not a Neon Number Explanation: square is 12*12 = 144 and sum of the digits of the square is 9 (1 + 4 + 4) which is not equal to 12.
The implementation is simple, we first compute square of given number, the find sum of digits in the square.
C++
// C/C++ program to check and print // Neon Numbers upto 10000 #include <iostream> using namespace std; #include <math.h> int checkNeon(int x) { // storing the square of x int sq = x * x; // calculating the sum of sum of digits // of sq int sum_digits = 0; while (sq != 0) { sum_digits = sum_digits + sq % 10; sq = sq / 10; } return (sum_digits == x); } // Driver Code int main(void) { // Printing Neon Numbers upto 10000 for (int i = 1; i <= 10000; i++) if (checkNeon(i)) cout << i << " "; } |
Java
// Java program to check and print // Neon Numbers upto 10000 import java.io.*; class GFG { // function to check Neon Number static boolean checkNeon(int x) { // storing the square of x int sq = x * x; // calculating the sum of sum of digits // of sq int sum_digits = 0; while (sq != 0) { sum_digits = sum_digits + sq % 10; sq = sq / 10; } return (sum_digits == x); } // Driver Code public static void main(String args[]) throws IOException { // Printing Neon Numbers upto 10000 for (int i = 1; i <= 10000; i++) if (checkNeon(i)) System.out.print(i + " "); } } // This code is contributed by Nikita Tiwari. |
Python
# Python program to check and print # Neon Numbers upto 10000 # function to check Neon Number def checkNeon (x) : # storing the square of x sq = x * x # calculating the sum of sum of digits # of sq sum_digits = 0 while (sq != 0) : sum_digits = sum_digits + sq % 10 sq = sq / 10 return (sum_digits == x) # Driver Code i = 1# Printing Neon Numbers upto 10000 while i <= 10000 : if (checkNeon(i)) : print i, i = i + 1 # This code is contributed by Nikita Tiwari. |
C#
// C# program to check and print // Neon Numbers upto 10000 using System; class GFG { // function to check Neon Number static bool checkNeon(int x) { // storing the square of x int sq = x * x; // calculating the sum of sum of digits // of sq int sum_digits = 0; while (sq != 0) { sum_digits = sum_digits + sq % 10; sq = sq / 10; } return (sum_digits == x); } // Driver Code public static void Main() { // Printing Neon Numbers upto 10000 for (int i = 1; i <= 10000; i++) if (checkNeon(i)) Console.Write(i + " "); } } // This code is contributed by vt_m. |
PHP
<?php // PHP program to check and print // Neon Numbers upto 10000 function checkNeon($x) { // storing the square of x $sq = $x * $x; // calculating the sum of // sum of digits of sq $sum_digits = 0; while ($sq != 0) { $sum_digits = $sum_digits + $sq % 10; $sq = $sq / 10; } return ($sum_digits == $x); } // Driver Code // Printing Neon Numbers // upto 10000 for ($i = 1; $i <= 10000; $i++) if (checkNeon($i)) echo $i . " "; // This code is contributed by Sam007 ?> |
Output:
1 9
This article is contributed by Nikita Tiwari. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
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