# Line slope calculator x+3y=5

**Straight line given by points A[2; 1] and B[5; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.3333x+1.6667

**Canonical form of the line equation:**x+3y-5 = 0

**Parametric form of the line equation:**

x = 3t+2

y = -t+1 ; t ∈ R

**Slope:**m = -0.3333

**Slope angle of line: φ =**-18°26'6″ = -0.3218 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = 1.6667

**Distance line from the origin:**d

_{0}= 1.5811

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(3; -1)

**Normal vector: n =**(1; 3)

**Midpoint of the segment AB: M =**[3.5; 0.5]

**Perpendicular Bisector equation:**3x-y-10 = 0

**Vector OA = (2; 1) ; |OA| = 2.2361**

**Vector OB = (5; 0) ; |OB| = 5**

**Scalar product OA .OB = 10**

**Angle ∠ AOB = 26°33'54″ = 0.4636 rad**