Multiply a number with 10 without using multiplication operator

Given a number, the task is to multiply it with 10 without using multiplication operator?

Examples:

Input : n = 50
Output: 500
// multiplication of 50 with 10 is = 500

Input : n = 16
Output: 160
// multiplication of 16 with 10 is = 160



A simple solution for this problem is to run a loop and add n with itself 10 times. Here we need to perform 10 operations.
A better solution is to use bit manipulation. We have to multiply n with 10 i.e; n*10, we can write this as n*(2+8) = n*2 + n*8 and since we are not allowed to use multiplication operator we can do this using left shift bitwise operator. So n*10 = n<<1 + n<<3.

C++

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// C++ program to multiply a number with 10 using
// bitwise operators
#include<bits/stdc++.h>
using namespace std;
  
// Function to find multiplication of n with
// 10 without usng multiplication operator
int multiplyTen(int n)
{
    return (n<<1) + (n<<3);
}
  
// Driver program to run the case
int main()
{
    int n = 50;
    cout << multiplyTen(n);
    return 0;
}

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Java

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// Java Code to Multiply a number with 10
// without using multiplication operator
import java.util.*;
  
class GFG {
      
    // Function to find multiplication of n 
    // with 10 without usng multiplication
    // operator
    public static int multiplyTen(int n)
    {
        return (n << 1) + (n << 3);
    }
      
    /* Driver program to test above function */
    public static void main(String[] args) 
    {
        int n = 50;
        System.out.println(multiplyTen(n));
         
    }
}
    
// This code is contributed by Arnav Kr. Mandal.

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Python 3

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# Python 3 program to multiply a 
# number with 10 using bitwise
# operators
  
# Function to find multiplication
# of n with 10 without usng
# multiplication operator
def multiplyTen(n):
  
    return (n << 1) + (n << 3)
  
# Driver program to run the case
n = 50
print (multiplyTen(n))
  
# This code is contributed by 
# Smitha

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C#

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// C# Code to Multiply a number with 10
// without using multiplication operator
using System;
  
class GFG {
      
    // Function to find multiplication of n 
    // with 10 without usng multiplication
    // operator
    public static int multiplyTen(int n)
    {
        return (n << 1) + (n << 3);
    }
      
    // Driver Code
    public static void Main() 
    {
        int n = 50;
        Console.Write(multiplyTen(n));
          
    }
}
      
// This code is contributed by Nitin Mittal.

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PHP

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<?php
// PHP program to multiply a 
// number with 10 using
// bitwise operators
  
// Function to find multiplication 
// of n with 10 without using 
// multiplication operator
function multiplyTen($n)
{
    return ($n << 1) + ($n << 3);
}
  
    // Driver Code
    $n = 50;
    echo multiplyTen($n);
  
// This code is contributed by nitin mittal. 
?>

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Output:

500

This article is contributed by Shashank Mishra ( Gullu ). If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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