Multiples of 3 and 5 without using % operator

Write a short program that prints each number from 1 to n on a new line.

  1. For each multiple of 3, print “Multiple of 3” instead of the number.
  2. For each multiple of 5, print “Multiple of 5” instead of the number.
  3. For numbers which are multiples of both 3 and 5, print “Multiple of 3. Multiple of 5.” instead of the number.

Examples:

Input  : 15 
Output : 1
         2
         Multiple of 3.
         4
         Multiple of 5.
         Multiple of 3.
         7
         8
         Multiple of 3.
         Multiple of 5.
         11
         Multiple of 3.
         13
         14
         Multiple of 3. Multiple of 5.


The idea is iterate from 1 to n and keep track of multiples of 3 and 5 by adding 3 and 5 to current multiple. If current number matches with a multiple, we update our output accordingly.

Java

// Java program to print multiples of 3 and
// 5 without using % operator.
import java.io.*;
  
class GFG
{
    static void findMultiples(int n)
    {
        int a = 3// To keep track of multiples of 3
        int b = 5// To keep track of multiples of 5
        for (int i=1; i<=n; i++)
        {
            String s = "";
  
            // Found multiple of 3
            if (i==a)
            {
                a = a + 3// Update next multiple of 3
                s = s + "Multiple of 3. ";
            }
  
            // Found multiple of 5
            if (i==b)
            {
                b = b+5// Update next multiple of 5
                s = s + "Multiple of 5.";
            }
  
            if (s == "")
                System.out.println(i);
            else  System.out.println(s);
        }
    }
  
    public static void main (String[] args)
    {
        findMultiples(20);
    }
}

C#

// C# program to print multiples of 3 and
// 5 without using % operator.
using System;
  
public class GFG {
      
    static void findMultiples(int n)
    {
          
        // To keep track of multiples of 3
        int a = 3;
          
        // To keep track of multiples of 5
        int b = 5;
        for (int i = 1; i <= n; i++)
        {
            String s = "";
  
            // Found multiple of 3
            if (i == a)
            {
                  
                // Update next multiple of 3
                a = a + 3;
                s = s + "Multiple of 3. ";
            }
  
            // Found multiple of 5
            if (i == b)
            {
                  
                // Update next multiple of 5
                b = b + 5;
                s = s + "Multiple of 5.";
            }
  
            if (s == "")
                Console.WriteLine(i);
            else
                Console.WriteLine(s);
        }
    }
  
    // Driver code
    public static void Main ()
    {
        findMultiples(20);
    }
}
  
// This code is contributed by Sam007.

Output:

1
2
Multiple of 3. 
4
Multiple of 5.
Multiple of 3. 
7
8
Multiple of 3. 
Multiple of 5.
11
Multiple of 3. 
13
14
Multiple of 3. Multiple of 5.
16
17
Multiple of 3. 
19
Multiple of 5.

This article is contributed by Nimish Jain. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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My Personal Notes arrow_drop_up

Improved By : Sam007



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