# Move all zeroes to end of array using List Comprehension in Python

Given an array of random numbers, Push all the zeros of a given array to the end of the array. For example, if the given arrays is {1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0}, it should be changed to {1, 9, 8, 4, 2, 7, 6, 0, 0, 0, 0}. The order of all other elements should be same. Expected time complexity is O(n) and extra space is O(1).

Examples:

Input : arr = [1, 2, 0, 4, 3, 0, 5, 0] Output : arr = [1, 2, 4, 3, 5, 0, 0, 0] Input : arr = [1, 2, 0, 0, 0, 3, 6] Output : arr = [1, 2, 3, 6, 0, 0, 0]

We have existing solution for this problem please refer Move all zeroes to end of array link. We will solve this problem in python using List Comprehension in a single line of code.

`# Function to append all zeros at the end ` `# of array` `def` `moveZeros(arr):` ` ` ` ` `# first expression returns a list of` ` ` `# all non zero elements in arr in the ` ` ` `# same order they were inserted into arr` ` ` `# second expression returns a list of ` ` ` `# zeros present in arr` ` ` `return` `[nonZero ` `for` `nonZero ` `in` `arr ` `if` `nonZero!` `=` `0` `] ` `+` `\` ` ` `[Zero ` `for` `Zero ` `in` `arr ` `if` `Zero` `=` `=` `0` `]` ` ` `# Driver function` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `arr ` `=` `[` `1` `, ` `2` `, ` `0` `, ` `4` `, ` `3` `, ` `0` `, ` `5` `, ` `0` `]` ` ` `print` `(moveZeros(arr))` |

Output:

[1, 2, 4, 3, 5, 0, 0, 0]

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