# Move all zeroes to end of array using List Comprehension in Python

Given an array of random numbers, Push all the zeros of a given array to the end of the array. For example, if the given arrays is {1, 9, 8, 4, 0, 0, 2, 7, 0, 6, 0}, it should be changed to {1, 9, 8, 4, 2, 7, 6, 0, 0, 0, 0}. The order of all other elements should be same. Expected time complexity is O(n) and extra space is O(1).

Examples:

```Input :  arr = [1, 2, 0, 4, 3, 0, 5, 0]
Output : arr = [1, 2, 4, 3, 5, 0, 0, 0]

Input : arr  = [1, 2, 0, 0, 0, 3, 6]
Output : arr = [1, 2, 3, 6, 0, 0, 0]
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

We have existing solution for this problem please refer Move all zeroes to end of array link. We will solve this problem in python using List Comprehension in a single line of code.

 `# Function to append all zeros at the end  ` `# of array ` `def` `moveZeros(arr): ` `     `  `    ``# first expression returns a list of ` `    ``# all non zero elements in arr in the  ` `    ``# same order they were inserted into arr ` `    ``# second expression returns a list of  ` `    ``# zeros present in arr ` `    ``return` `[nonZero ``for` `nonZero ``in` `arr ``if` `nonZero!``=``0``] ``+` `\ ` `           ``[Zero ``for` `Zero ``in` `arr ``if` `Zero``=``=``0``] ` ` `  `# Driver function ` `if` `__name__ ``=``=` `"__main__"``: ` `    ``arr ``=` `[``1``, ``2``, ``0``, ``4``, ``3``, ``0``, ``5``, ``0``] ` `    ``print` `(moveZeros(arr)) `

Output:

```[1, 2, 4, 3, 5, 0, 0, 0]
```

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