# Modulus of two float or double numbers

Given two floating-point numbers, find the remainder.

Examples:

Input: a = 36.5, b = 5.0
Output: 1.5

Input: a = 9.7, b = 2.3
Output: 0.5

## Recommended: Please solve it on PRACTICE first, before moving on to the solution.

A simple solution is to do repeated subtraction.

## C++

 `// CPP program to find modulo of floating  ` `// point numbers. ` `#include ` `using` `namespace` `std; ` ` `  `double` `findMod(``double` `a, ``double` `b) ` `{ ` `    ``double` `mod; ` `    ``// Handling negative values ` `    ``if` `(a < 0) ` `        ``mod = -a; ` `    ``else` `        ``mod =  a; ` `    ``if` `(b < 0) ` `        ``b = -b; ` ` `  `    ``// Finding mod by repeated subtraction ` `     `  `    ``while` `(mod >= b) ` `        ``mod = mod - b; ` ` `  `    ``// Sign of result typically depends ` `    ``// on sign of a. ` `    ``if` `(a < 0) ` `        ``return` `-mod; ` ` `  `    ``return` `mod; ` `} ` ` `  `// Driver Function ` `int` `main() ` `{ ` `    ``double` `a = 9.7, b = 2.3; ` `    ``cout << findMod(a, b); ` `    ``return` `0; ` `} `

## Java

 `// Java program to find modulo of floating  ` `// point numbers ` ` `  `class` `GFG ` `{ ` `    ``static` `double` `findMod(``double` `a, ``double` `b) ` `    ``{ ` `        ``// Handling negative values ` `        ``if` `(a < ``0``) ` `            ``a = -a; ` `        ``if` `(b < ``0``) ` `            ``b = -b; ` `     `  `        ``// Finding mod by repeated subtraction ` `        ``double` `mod = a; ` `        ``while` `(mod >= b) ` `            ``mod = mod - b; ` `     `  `        ``// Sign of result typically depends ` `        ``// on sign of a. ` `        ``if` `(a < ``0``) ` `            ``return` `-mod; ` `     `  `        ``return` `mod; ` `    ``} ` `     `  `    ``// Driver code  ` `    ``public` `static` `void` `main (String[] args) ` `    ``{ ` `        ``double` `a = ``9.7``, b = ``2.3``; ` `        ``System.out.print(findMod(a, b)); ` `    ``} ` `} ` ` `  `// This code is contributed by Anant Agarwal. `

## Python3

 `# Python3 program to find modulo  ` `# of floating point numbers. ` ` `  `def` `findMod(a, b): ` ` `  `    ``# Handling negative values ` `    ``if` `(a < ``0``): ` `        ``a ``=` `-``a ` `    ``if` `(b < ``0``): ` `        ``b ``=` `-``b ` ` `  `    ``# Finding mod by repeated subtraction ` `    ``mod ``=` `a ` `    ``while` `(mod >``=` `b): ` `        ``mod ``=` `mod ``-` `b ` ` `  `    ``# Sign of result typically  ` `    ``# depends on sign of a. ` `    ``if` `(a < ``0``): ` `        ``return` `-``mod ` ` `  `    ``return` `mod ` ` `  `# Driver code ` `a ``=` `9.7``; b ``=` `2.3` `print``(findMod(a, b)) ` ` `  `# This code is contributed by Anant Agarwal. `

## C#

 `// C# program to find modulo of floating  ` `// point numbers ` `using` `System; ` ` `  `class` `GFG { ` `     `  `    ``static` `double` `findMod(``double` `a, ``double` `b) ` `    ``{ ` `         `  `        ``// Handling negative values ` `        ``if` `(a < 0) ` `            ``a = -a; ` `        ``if` `(b < 0) ` `            ``b = -b; ` `     `  `        ``// Finding mod by repeated subtraction ` `        ``double` `mod = a; ` `        ``while` `(mod >= b) ` `            ``mod = mod - b; ` `     `  `        ``// Sign of result typically depends ` `        ``// on sign of a. ` `        ``if` `(a < 0) ` `            ``return` `-mod; ` `     `  `        ``return` `mod; ` `    ``} ` `     `  `    ``// Driver code  ` `    ``public` `static` `void` `Main () ` `    ``{ ` `         `  `        ``double` `a = 9.7, b = 2.3; ` `         `  `        ``Console.WriteLine(findMod(a, b)); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

## PHP

 `= ``\$b``) ` `        ``\$mod` `= ``\$mod` `- ``\$b``; ` ` `  `    ``// Sign of result typically  ` `    ``// depends on sign of a. ` `    ``if` `(``\$a` `< 0) ` `        ``return` `-``\$mod``; ` ` `  `    ``return` `\$mod``; ` `} ` ` `  `    ``// Driver Code ` `    ``\$a` `= 9.7; ``\$b` `= 2.3; ` `    ``echo` `findMod(``\$a``, ``\$b``); ` `     `  `// This code is contributed by anuj_65. ` `?> `

Output :

`0.5`

We can use the inbuilt fmod function to find the modulus of two floating-point numbers.

## C++

 `// CPP program to find modulo of floating  ` `// point numbers using library function. ` `#include ` `using` `namespace` `std; ` ` `  `// Driver Function ` `int` `main() ` `{ ` `    ``double` `a = 9.7, b = 2.3; ` `    ``cout << ``fmod``(a, b); ` `    ``return` `0; ` `} `

## PHP

 ` `

Output:

```0.5
```

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