# Modulus of all pairwise consecutive elements in an Array

Given an array of elements. The task is to print the modulus of all of the pairwise consecutive elements. That is for all pair of consecutive elements say ((a[i], a[i+1])), print (a[i] % a[i+1]).

Note: Consecutive pairs of an array of size N are (a[i], a[i+1]) for all i ranging from 0 to N-2.

Examples:

Input: arr[] = {8, 5, 4, 3, 15, 20}
Output: 3 1 1 3 15

Input: arr[] = {5, 10, 15, 20}
Output: 5 10 15

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The solution is to traverse the array and calculate and print the modulus of every pair (arr[i], arr[i+1]).

Below is the implementation of the above approach:

 // C++ program to print the modulus // of the consecutive elements #include using namespace std;    // Function to print pairwise modulus // of consecutive elements void pairwiseModulus(int arr[], int n) {     for (int i = 0; i < n - 1; i++) {            // Modulus of consecutive numbers         cout << (arr[i] % arr[i + 1]) << " ";     } }    // Driver Code int main() {     int arr[] = { 8, 5, 4, 3, 15, 20 };     int n = sizeof(arr) / sizeof(arr[0]);        pairwiseModulus(arr, n);        return 0; }

 // Java program to print the modulus // of the consecutive elements import java.util.*;    class Geeks {        // Function to print pairwise modulus // of consecutive elements static void pairwiseModulus(int arr[], int n) {     for (int i = 0; i < n - 1; i++) {            // Modulus of consecutive numbers         System.out.println((arr[i] % arr[i + 1]));     } }    // Driver Code public static void main(String args[]) {     int arr[] = { 8, 5, 4, 3, 15, 20 };     int n = arr.length;        pairwiseModulus(arr, n); } }    // This code is contributed by ankita_saini

 # Python 3 program to print the modulus # of the consecutive elements    # Function to print pairwise modulus # of consecutive elements def pairwiseModulus(arr, n):     for i in range(0, n - 1, 1):                    # Modulus of consecutive numbers         print((arr[i] % arr[i + 1]),                           end = " ")        # Driver Code if __name__ == '__main__':     arr = [8, 5, 4, 3, 15, 20]      n = len(arr)     pairwiseModulus(arr, n)    # This code is contributed  # by Surendra_Gangwar

 // C# program to print the modulus // of the consecutive elements using System;    class Geeks {        // Function to print pairwise modulus // of consecutive elements static void pairwiseModulus(int[] arr, int n) {     for (int i = 0; i < n - 1; i++) {            // Modulus of consecutive numbers         Console.WriteLine((arr[i] % arr[i + 1]));     } }    // Driver Code public static void Main(String []args) {     int[] arr = {8, 5, 4, 3, 15, 20};     int n = arr.Length;        pairwiseModulus(arr, n); } }    // This code is contributed by ankita_saini



Output:
3 1 1 3 15

Time complexity : O(n)

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