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Modulus of all pairwise consecutive elements in an Array

  • Difficulty Level : Basic
  • Last Updated : 17 May, 2022

Given an array of N     elements. The task is to print the modulus of all of the pairwise consecutive elements. That is for all pair of consecutive elements say ((a[i], a[i+1])), print (a[i] % a[i+1]).
Note: Consecutive pairs of an array of size N are (a[i], a[i+1]) for all i ranging from 0 to N-2.
Examples
 

Input: arr[] = {8, 5, 4, 3, 15, 20}
Output: 3 1 1 3 15 

Input: arr[] = {5, 10, 15, 20}
Output: 5 10 15 

 

Approach: The solution is to traverse the array and calculate and print the modulus of every pair (arr[i], arr[i+1]).
Below is the implementation of the above approach: 
 

C++




// C++ program to print the modulus
// of the consecutive elements
#include <iostream>
using namespace std;
 
// Function to print pairwise modulus
// of consecutive elements
void pairwiseModulus(int arr[], int n)
{
    for (int i = 0; i < n - 1; i++) {
 
        // Modulus of consecutive numbers
        cout << (arr[i] % arr[i + 1]) << " ";
    }
}
 
// Driver Code
int main()
{
    int arr[] = { 8, 5, 4, 3, 15, 20 };
    int n = sizeof(arr) / sizeof(arr[0]);
 
    pairwiseModulus(arr, n);
 
    return 0;
}

C




// C program to print the modulus
// of the consecutive elements
#include <stdio.h>
 
// Function to print pairwise modulus
// of consecutive elements
void pairwiseModulus(int arr[], int n)
{
    for (int i = 0; i < n - 1; i++) {
 
        // Modulus of consecutive numbers
        printf("%d ",arr[i] % arr[i + 1]);
    }
}
 
// Driver Code
int main()
{
    int arr[] = { 8, 5, 4, 3, 15, 20 };
    int n = sizeof(arr) / sizeof(arr[0]);
 
    pairwiseModulus(arr, n);
 
    return 0;
}
 
// This code is contributed by kothavvsaakash.

Java




// Java program to print the modulus
// of the consecutive elements
import java.util.*;
 
class Geeks {
     
// Function to print pairwise modulus
// of consecutive elements
static void pairwiseModulus(int arr[], int n)
{
    for (int i = 0; i < n - 1; i++) {
 
        // Modulus of consecutive numbers
        System.out.println((arr[i] % arr[i + 1]));
    }
}
 
// Driver Code
public static void main(String args[])
{
    int arr[] = { 8, 5, 4, 3, 15, 20 };
    int n = arr.length;
 
    pairwiseModulus(arr, n);
}
}
 
// This code is contributed by ankita_saini

Python3




# Python 3 program to print the modulus
# of the consecutive elements
 
# Function to print pairwise modulus
# of consecutive elements
def pairwiseModulus(arr, n):
    for i in range(0, n - 1, 1):
         
        # Modulus of consecutive numbers
        print((arr[i] % arr[i + 1]),
                         end = " ")
     
# Driver Code
if __name__ == '__main__':
    arr = [8, 5, 4, 3, 15, 20]
    n = len(arr)
    pairwiseModulus(arr, n)
 
# This code is contributed
# by Surendra_Gangwar

C#




// C# program to print the modulus
// of the consecutive elements
using System;
 
class Geeks {
     
// Function to print pairwise modulus
// of consecutive elements
static void pairwiseModulus(int[] arr, int n)
{
    for (int i = 0; i < n - 1; i++) {
 
        // Modulus of consecutive numbers
        Console.WriteLine((arr[i] % arr[i + 1]));
    }
}
 
// Driver Code
public static void Main(String []args)
{
    int[] arr = {8, 5, 4, 3, 15, 20};
    int n = arr.Length;
 
    pairwiseModulus(arr, n);
}
}
 
// This code is contributed by ankita_saini

PHP




<?php
//PHP program to print the modulus
// of the consecutive elements
 
// Function to print pairwise modulus
// of consecutive elements
function pairwiseModulus( $arr, $n)
{
    for ($i = 0; $i < $n - 1; $i++) {
 
        // Modulus of consecutive numbers
        echo  ($arr[$i] % $arr[$i + 1]), " ";
    }
}
 
// Driver Code
    $arr = array( 8, 5, 4, 3, 15, 20 );
    $n = sizeof($arr) / sizeof($arr[0]);
 
    pairwiseModulus($arr, $n);
 
 
// This code is contributed by ajit
?>

Javascript




<script>
// javascript program to print the modulus
// of the consecutive elementsclass Geeks {
 
    // Function to print pairwise modulus
    // of consecutive elements
    function pairwiseModulus(arr , n) {
        for (i = 0; i < n - 1; i++) {
 
            // Modulus of consecutive numbers
            document.write((arr[i] % arr[i + 1]) + " ");
        }
    }
 
    // Driver Code
     
        var arr = [ 8, 5, 4, 3, 15, 20 ];
        var n = arr.length;
 
        pairwiseModulus(arr, n);
 
// This code contributed by gauravrajput1
</script>
Output: 
3 1 1 3 15

 

Time complexity : O(n)
 Auxiliary Space: O(1)


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