Given a number n, a position p and a binary value b, we need to change the bit at position p in n to value b.
Input : n = 7, p = 2, b = 0 Output : 3 7 is 00000111 after clearing bit at 2rd position, it becomes 0000011. Input : n = 7, p = 3, b = 1 Output : 15 7 is 00000111 after setting bit at 3rd position it becomes 00001111.
We first create a mask that has set bit only at given position using bit wise shift. mask = 1 << position Then to change value of bit to b, we first make it 0 using below operation value & ~mask After changing it 0, we change it to b by doing or of above expression with following (b << p) & mask, i.e., we return ((n & ~mask) | (b << p))
Below is the implementation of above steps :
Time Complexity :O(1)
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