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Program for triangular pattern (mirror image around 0)
  • Difficulty Level : Medium
  • Last Updated : 18 Apr, 2018

Given the value of n, print the pattern.

Examples :

Input : n = 5
Output : 
    0
   101
  21012
 3210123
432101234

Input : n = 7
Output : 
      0
     101
    21012
   3210123
  432101234
 54321012345
6543210123456

Below is the program to print the above pattern

C++

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// C++ Implementation to print the pattern
#include <bits/stdc++.h>
using namespace std;
  
// Function definition
void print(int n)
{
    int var1 = 1, var2 = 1;
  
    // Outer for loop to keep
    // track of number of lines
    for (int i = 0; i < n; i++) {
        // for loop to keep track
        // of spaces
        for (int j = n - 1; j > i; j--) {
            cout << " ";
        }
  
        // for loop to print the
        // digits in pattern
        for (int k = 1; k <= var1; k++) {
            cout << abs(k - var2);
        }
  
        var1 += 2;
        var2++;
        cout << "\n";
    }
}
  
// Driver code
int main()
{
    // taking size from the user
    int n = 5;
  
    // function calling
    print(n);
      
    return 0;
}

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Java

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// Java Implementation to print the pattern
  
class GFG
{
    // Function definition
    static void print(int n)
    {
        int var1 = 1, var2 = 1;
      
        // Outer for loop to keep
        // track of number of lines
        for (int i = 0; i < n; i++) 
        {
            // for loop to keep track
            // of spaces
            for (int j = n - 1; j > i; j--) 
            {
                System.out.print(" ");
            }
      
            // for loop to print the
            // digits in pattern
            for (int k = 1; k <= var1; k++) 
            {
                System.out.print(Math.abs(k - var2));
            }
      
            var1 += 2;
            var2++;
            System.out.println();
        }
    }
      
    // Driver code
    public static void main (String[] args) 
    {
        // taking size from the user
        int n = 5;
      
        // function calling
        print(n);
    }
}
  
// This code is contributed by Anant Agarwal.

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Python3

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# Python Implementation to 
# print the pattern
  
# Function definition
def printt(n):
  
    var1 = 1
    var2 = 1
   
    # Outer for loop to keep
    # track of number of lines
    for i in range(n):
  
        # for loop to keep track
        # of spaces
        for j in range(n - 1,i,-1):
            print(" ", end = "")
  
        # for loop to print the
        # digits in pattern
        for k in range(1, var1 + 1):
            print(abs(k - var2), end="")
          
        var1 += 2
        var2 += 1
        print()
  
# Driver code
# taking size from the user
n = 5
   
# function calling
printt(n)
  
# This code is contributed
# by Anant Agarwal.

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C#

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//C# Implementation to print the pattern
using System;
class GFG
{
    // Function definition
    static void print(int n)
    {
        int var1 = 1, var2 = 1;
      
        // Outer for loop to keep
        // track of number of lines
        for (int i = 0; i < n; i++) 
        {
            // for loop to keep track
            // of spaces
            for (int j = n - 1; j > i; j--) 
            {
                Console.Write(" ");
            }
      
            // for loop to print the
            // digits in pattern
            for (int k = 1; k <= var1; k++) 
            {
            Console.Write(Math.Abs(k - var2));
            }
      
            var1 += 2;
            var2++;
            Console.WriteLine();
        }
    }
      
    // Driver code
    public static void Main () 
    {
        // taking size from the user
        int n = 5;
      
        // function calling
        print(n);
    }
}
  
// This code is contributed by vt_m.

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PHP

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<?php
// PHP Implementation to
// print the pattern
  
// Function definition
function print1($n)
{
    $var1 = 1;
    $var2 = 1;
  
    // Outer for loop to keep
    // track of number of lines
    for ($i = 0; $i < $n; $i++) 
    {
        // for loop to keep track
        // of spaces
        for ($j = $n - 1; $j > $i; $j--) 
        {
            echo " ";
        }
  
        // for loop to print the
        // digits in pattern
        for ($k = 1; $k <= $var1; $k++) 
        {
            echo abs($k - $var2);
        }
  
        $var1 += 2;
        $var2++;
        echo "\n";
    }
}
  
// Driver code
$n = 5;
print1($n);
  
// This code is contributed by mits 
?>

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Output :

    0
   101
  21012
 3210123
432101234



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