Given three integers N, X and Y, the task is to find the minimum integer that should be added to X to make it at least Y percent of N.
Input: N = 10, X = 2, Y = 40
Adding 2 to X gives 4 which is 40% of 10
Input: N = 10, X = 2, Y = 20
X is already 20% of 10
Approach: Find val = (N * Y) / 100 which is the Y percent of N. Now in order for X to be equal to val, val – X must be added to X only if X < val.
Below is the implementation of the above approach:
Time Complexity: O(1)
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