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# Minimum value of maximum absolute difference of all adjacent pairs in an Array

• Last Updated : 21 Apr, 2021

Given an array arr, containing non-negative integers and (-1)s, of size N, the task is to replace those (-1)s with a common non-negative integer such that the maximum absolute difference of all adjacent pairs is minimum. Print this minimum possible value of the maximum absolute difference.

Examples:

Input: arr = {-1, -1, 11, -1, 3, -1}
Output:
Replace every -1 element with 7. Now the maximum absolute difference of all adjacent pairs is minimum which is equal to 4

Input: arr = {4, -1}
Output:

Approach:

1. Consider only those non-missing elements that are adjacent to at least one missing element.
2. Find the maximum element and the minimum element among them.
3. We need to find a value that minimizes the maximum absolute difference between the common value and these values.
4. The optimal value is equals to
`(minimum element + maximum element) / 2`

Below is the implementation of the above approach:

## C++

 `// C++ program to find the minimum value``// of maximum absolute difference of``// all adjacent pairs in an Array``#include ``using` `namespace` `std;` `// Function to find the minimum possible``// value of the maximum absolute difference.``int` `maximumAbsolute(``int` `arr[], ``int` `n)``{``    ``// To store minimum and maximum elements``    ``int` `mn = INT_MAX;``    ``int` `mx = INT_MIN;` `    ``for` `(``int` `i = 0; i < n; i++) {``        ``// If right side element is equals -1``        ``// and left side is not equals -1``        ``if` `(i > 0``            ``&& arr[i] == -1``            ``&& arr[i - 1] != -1) {``            ``mn = min(mn, arr[i - 1]);``            ``mx = max(mx, arr[i - 1]);``        ``}` `        ``// If left side element is equals -1``        ``// and right side is not equals -1``        ``if` `(i < n - 1``            ``&& arr[i] == -1``            ``&& arr[i + 1] != -1) {``            ``mn = min(mn, arr[i + 1]);``            ``mx = max(mx, arr[i + 1]);``        ``}``    ``}` `    ``// Calculating the common integer``    ``// which needs to be replaced with``    ``int` `common_integer = (mn + mx) / 2;` `    ``// Replace all -1 elements``    ``// with the common integer``    ``for` `(``int` `i = 0; i < n; i++) {``        ``if` `(arr[i] == -1)``            ``arr[i] = common_integer;``    ``}` `    ``int` `max_diff = 0;` `    ``// Calculating the maximum``    ``// absolute difference``    ``for` `(``int` `i = 0; i < n - 1; i++) {``        ``int` `diff = ``abs``(arr[i] - arr[i + 1]);` `        ``if` `(diff > max_diff)``            ``max_diff = diff;``    ``}` `    ``// Return the maximum absolute difference``    ``return` `max_diff;``}` `// Driver Code``int` `main()``{``    ``int` `arr[] = { -1, -1, 11, -1, 3, -1 };``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr);` `    ``// Function call``    ``cout << maximumAbsolute(arr, n);` `    ``return` `0;``}`

## Java

 `// Java program to find the minimum value``// of maximum absolute difference of``// all adjacent pairs in an Array``import` `java.util.*;` `class` `GFG{`` ` `// Function to find the minimum possible``// value of the maximum absolute difference.``static` `int` `maximumAbsolute(``int` `arr[], ``int` `n)``{``    ``// To store minimum and maximum elements``    ``int` `mn = Integer.MAX_VALUE;``    ``int` `mx = Integer.MIN_VALUE;`` ` `    ``for` `(``int` `i = ``0``; i < n; i++) {` `        ``// If right side element is equals -1``        ``// and left side is not equals -1``        ``if` `(i > ``0``            ``&& arr[i] == -``1``            ``&& arr[i - ``1``] != -``1``) {``            ``mn = Math.min(mn, arr[i - ``1``]);``            ``mx = Math.max(mx, arr[i - ``1``]);``        ``}`` ` `        ``// If left side element is equals -1``        ``// and right side is not equals -1``        ``if` `(i < n - ``1``            ``&& arr[i] == -``1``            ``&& arr[i + ``1``] != -``1``) {``            ``mn = Math.min(mn, arr[i + ``1``]);``            ``mx = Math.max(mx, arr[i + ``1``]);``        ``}``    ``}`` ` `    ``// Calculating the common integer``    ``// which needs to be replaced with``    ``int` `common_integer = (mn + mx) / ``2``;`` ` `    ``// Replace all -1 elements``    ``// with the common integer``    ``for` `(``int` `i = ``0``; i < n; i++) {``        ``if` `(arr[i] == -``1``)``            ``arr[i] = common_integer;``    ``}`` ` `    ``int` `max_diff = ``0``;`` ` `    ``// Calculating the maximum``    ``// absolute difference``    ``for` `(``int` `i = ``0``; i < n - ``1``; i++) {``        ``int` `diff = Math.abs(arr[i] - arr[i + ``1``]);`` ` `        ``if` `(diff > max_diff)``            ``max_diff = diff;``    ``}`` ` `    ``// Return the maximum absolute difference``    ``return` `max_diff;``}`` ` `// Driver Code``public` `static` `void` `main(String[] args)``{``    ``int` `arr[] = { -``1``, -``1``, ``11``, -``1``, ``3``, -``1` `};``    ``int` `n = arr.length;`` ` `    ``// Function call``    ``System.out.print(maximumAbsolute(arr, n));``}``}` `// This code is contributed by Rajput-Ji`

## Python3

 `# Python3 program to find the minimum value``# of maximum absolute difference of``# all adjacent pairs in an Array` `# Function to find the minimum possible``# value of the maximum absolute difference.``def` `maximumAbsolute(arr, n):` `    ``# To store minimum and maximum elements``    ``mn ``=` `10``*``*``9``    ``mx ``=` `-``10``*``*``9` `    ``for` `i ``in` `range``(n):``    ` `        ``# If right side element is equals -1``        ``# and left side is not equals -1``        ``if` `(i > ``0``            ``and` `arr[i] ``=``=` `-``1``            ``and` `arr[i ``-` `1``] !``=` `-``1``):``            ``mn ``=` `min``(mn, arr[i ``-` `1``])``            ``mx ``=` `max``(mx, arr[i ``-` `1``])` `        ``# If left side element is equals -1``        ``# and right side is not equals -1``        ``if` `(i < n ``-` `1``            ``and` `arr[i] ``=``=` `-``1``            ``and` `arr[i ``+` `1``] !``=` `-``1``):``            ``mn ``=` `min``(mn, arr[i ``+` `1``])``            ``mx ``=` `max``(mx, arr[i ``+` `1``])` `    ``# Calculating the common integer``    ``# which needs to be replaced with``    ``common_integer ``=` `(mn ``+` `mx) ``/``/` `2` `    ``# Replace all -1 elements``    ``# with the common integer``    ``for` `i ``in` `range``(n):``        ``if` `(arr[i] ``=``=` `-``1``):``            ``arr[i] ``=` `common_integer` `    ``max_diff ``=` `0` `    ``# Calculating the maximum``    ``# absolute difference``    ``for` `i ``in` `range``(n``-``1``):``        ``diff ``=` `abs``(arr[i] ``-` `arr[i ``+` `1``])` `        ``if` `(diff > max_diff):``            ``max_diff ``=` `diff` `    ``# Return the maximum absolute difference``    ``return` `max_diff` `# Driver Code``if` `__name__ ``=``=` `'__main__'``:``    ``arr``=``[``-``1``, ``-``1``, ``11``, ``-``1``, ``3``, ``-``1``]``    ``n ``=` `len``(arr)` `    ``# Function call``    ``print``(maximumAbsolute(arr, n))` `# This code is contributed by mohit kumar 29`

## C#

 `// C# program to find the minimum value``// of maximum absolute difference of``// all adjacent pairs in an Array``using` `System;` `class` `GFG{`` ` `    ``// Function to find the minimum possible``    ``// value of the maximum absolute difference.``    ``static` `int` `maximumAbsolute(``int` `[]arr, ``int` `n)``    ``{``        ``// To store minimum and maximum elements``        ``int` `mn = ``int``.MaxValue;``        ``int` `mx = ``int``.MinValue;``     ` `        ``for` `(``int` `i = 0; i < n; i++) {``    ` `            ``// If right side element is equals -1``            ``// and left side is not equals -1``            ``if` `(i > 0``                ``&& arr[i] == -1``                ``&& arr[i - 1] != -1) {``                ``mn = Math.Min(mn, arr[i - 1]);``                ``mx = Math.Max(mx, arr[i - 1]);``            ``}``     ` `            ``// If left side element is equals -1``            ``// and right side is not equals -1``            ``if` `(i < n - 1``                ``&& arr[i] == -1``                ``&& arr[i + 1] != -1) {``                ``mn = Math.Min(mn, arr[i + 1]);``                ``mx = Math.Max(mx, arr[i + 1]);``            ``}``        ``}``     ` `        ``// Calculating the common integer``        ``// which needs to be replaced with``        ``int` `common_integer = (mn + mx) / 2;``     ` `        ``// Replace all -1 elements``        ``// with the common integer``        ``for` `(``int` `i = 0; i < n; i++) {``            ``if` `(arr[i] == -1)``                ``arr[i] = common_integer;``        ``}``     ` `        ``int` `max_diff = 0;``     ` `        ``// Calculating the maximum``        ``// absolute difference``        ``for` `(``int` `i = 0; i < n - 1; i++) {``            ``int` `diff = Math.Abs(arr[i] - arr[i + 1]);``     ` `            ``if` `(diff > max_diff)``                ``max_diff = diff;``        ``}``     ` `        ``// Return the maximum absolute difference``        ``return` `max_diff;``    ``}``     ` `    ``// Driver Code``    ``public` `static` `void` `Main(``string``[] args)``    ``{``        ``int` `[]arr = { -1, -1, 11, -1, 3, -1 };``        ``int` `n = arr.Length;``     ` `        ``// Function call``        ``Console.Write(maximumAbsolute(arr, n));``    ``}``}` `// This code is contributed by Yash_R`

## Javascript

 ``
Output:
`4`

Time complexity: O(N)

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