Given the no. of working hours of N people individually to complete a certain piece of work. The task is to find the number of hours they will take when all work together. **Examples:**

Input: n = 2, a = 6.0, b = 3.0 Output: 2 Hours Input: n = 3, a = 6.0, b = 3.0, c = 4.0 Output: 1.33333 Hours

**Solution:**

- If a person can do a piece of work in ‘n’ days, then in one day, the person will do ‘1/n’ work.
- Similarly If a person can do a piece of work in ‘m’ days, then in one day, the person will do ‘1/m’ work.
- So on…. for other persons.

**So, total work done by N persons in 1 day is**

1/n + 1/m + 1/p…… + 1/z

Where n, m, p ….., z are the number of days taken by each person respectively.

The result of the above expression will be the part of work done by all person together in 1 day, let’s saya / b.

To calculate the time taken to complete the whole work will beb / a.

**Consider an example of two persons:**

Time taken by 1st person to complete a work = 6 hours Time taken by 2nd person to complete the same work = 2 hours Work done by 1st person in 1 hour = 1/6 Work done by 2nd person in 1 hour = 1/2 So, total work done by them in 1 hour is => 1 / 6 + 1/ 2 => (2 + 6) / (2 * 6) => 8 / 12 So, to complete the whole work, the time taken will be 12/8.

## C++

`// C++ implementation of above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to calculate the time` `float` `calTime(` `float` `arr[], ` `int` `n)` `{` ` ` `float` `work = 0;` ` ` `for` `(` `int` `i = 0; i < n; i++)` ` ` `work += 1 / arr[i];` ` ` `return` `1 / work;` `}` `// Driver Code` `int` `main()` `{` ` ` `float` `arr[] = { 6.0, 3.0, 4.0 };` ` ` `int` `n = ` `sizeof` `(arr) / ` `sizeof` `(arr[0]);` ` ` `cout << calTime(arr, n) << ` `" Hours"` `;` ` ` `return` `0;` `}` |

## Java

`// Java implementation` `// of above approach` `import` `java.io.*;` `class` `GFG` `{` ` ` `// Function to calculate the time` `static` `double` `calTime(` `double` `arr[], ` `int` `n)` `{` ` ` `double` `work = ` `0` `;` ` ` `for` `(` `int` `i = ` `0` `; i < n; i++)` ` ` `work += ` `1` `/ arr[i];` ` ` `return` `1` `/ work;` `}` `// Driver Code` `public` `static` `void` `main (String[] args)` `{` ` ` `double` `arr[] = { ` `6.0` `, ` `3.0` `, ` `4.0` `};` ` ` `int` `n = arr.length;` ` ` ` ` `System.out.println(calTime(arr, n) +` ` ` `" Hours"` `);` `}` `}` `// This code is contributed` `// by inder_verma.` |

## Python3

`# Python3 implementation of` `# above approach` `# Function to calculate the time` `def` `calTime(arr, n):` ` ` `work ` `=` `0` ` ` `for` `i ` `in` `range` `(n):` ` ` `work ` `+` `=` `1` `/` `arr[i]` ` ` `return` `1` `/` `work` ` ` `# Driver Code` `arr ` `=` `[ ` `6.0` `, ` `3.0` `, ` `4.0` `]` `n ` `=` `len` `(arr)` `print` `(calTime(arr, n), ` `"Hours"` `)` `# This code is contributed` `# by Sanjit_Prasad` |

## C#

`// C# implementation` `// of above approach` `using` `System;` `class` `GFG` `{` ` ` `// Function to calculate the time` `static` `double` `calTime(` `double` `[]arr,` ` ` `int` `n)` `{` ` ` `double` `work = 0;` ` ` `for` `(` `int` `i = 0; i < n; i++)` ` ` `work += 1 / arr[i];` ` ` `return` `Math.Round(1 / work, 5);` `}` `// Driver Code` `public` `static` `void` `Main ()` `{` ` ` `double` `[]arr = { 6.0, 3.0, 4.0 };` ` ` `int` `n = arr.Length;` ` ` ` ` `Console.Write(calTime(arr, n) +` ` ` `" Hours"` `);` `}` `}` `// This code is contributed by Smitha` |

## PHP

`<?php` `// PHP implementation of above approach` `// Function to calculate the time` `function` `calTime(&` `$arr` `, ` `$n` `)` `{` ` ` `$work` `= 0;` ` ` `for` `(` `$i` `= 0; ` `$i` `< ` `$n` `; ` `$i` `++)` ` ` `$work` `+= 1 / ` `$arr` `[` `$i` `];` ` ` `return` `1 / ` `$work` `;` `}` `// Driver Code` `$arr` `= ` `array` `(6.0, 3.0, 4.0);` `$n` `= sizeof(` `$arr` `);` `echo` `calTime(` `$arr` `, ` `$n` `);` `echo` `" Hours"` `;` `// This code is contribuuted` `// by Shivi_Aggarwal` `?>` |

## Javascript

`<script>` `// javascript implementation` `// of above approach` ` ` `// Function to calculate the time` ` ` `function` `calTime(arr , n)` ` ` `{` ` ` `var` `work = 0;` ` ` `for` `(i = 0; i < n; i++)` ` ` `work += 1 / arr[i];` ` ` `return` `1 / work;` ` ` `}` ` ` `// Driver Code` ` ` ` ` `var` `arr = [ 6.0, 3.0, 4.0 ];` ` ` `var` `n = arr.length;` ` ` `document.write(calTime(arr, n).toFixed(5) + ` `" Hours"` `);` `// This code is contributed by Rajput-Ji.` `</script>` |

**Output:**

1.33333 Hours

**Note:** Here the input array contains hours, it can be days, minutes……so on.

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