# Minimum numbers (smaller than or equal to N) with sum S

Given N numbers(1, 2, 3, ….N) and a number S. The task is to print the minimum number of numbers that sum up to give S.

Examples:

Input: N = 5, S = 11
Output: 3
Three numbers (smaller than or equal to N) can be any of the given combinations.
(3, 4, 4)
(2, 4, 5)
(1, 5, 5)
(3, 3, 5)

Input: N = 1, S = 10
Output: 10

Approach: Greedily we choose N as many times we can, and then if anything less than N is left we will choose that number which adds up to give S, hence the total number of numbers are (S/N) + 1(if S%N>0).

Below is the implementation of the above approach.

## C++

 `// C++ program to find the minimum numbers ` `// required to get to S ` `#include ` `using` `namespace` `std; ` ` `  `// Function to find the minimum ` `// numbers required to get to S ` `int` `minimumNumbers(``int` `n, ``int` `s) ` `{ ` `    ``if` `(s % n) ` `        ``return` `s / n + 1; ` `    ``else` `        ``return` `s / n; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 5; ` `    ``int` `s = 11; ` `    ``cout << minimumNumbers(n, s); ` `    ``return` `0; ` `} `

## Java

 `// Java program to find the minimum numbers ` `// required to get to S ` `import` `java.io.*; ` ` `  `class` `GFG { ` `     `  ` `  `// Function to find the minimum ` `// numbers required to get to S ` `static` `int` `minimumNumbers(``int` `n, ``int` `s) ` `{ ` `    ``if` `((s % n)>``0``) ` `        ``return` `s / n + ``1``; ` `    ``else` `        ``return` `s / n; ` `} ` ` `  `// Driver Code ` ` `  `    ``public` `static` `void` `main (String[] args) { ` `        ``int` `n = ``5``; ` `    ``int` `s = ``11``; ` `    ``System.out.println(minimumNumbers(n, s)); ` `    ``} ` `} ` `// This code is contributed by shs.. `

## Python 3

 `# Python 3 program to find the  ` `# minimum numbers required to get to S ` ` `  `# Function to find the minimum ` `# numbers required to get to S ` `def` `minimumNumbers(n, s): ` ` `  `    ``if` `(s ``%` `n): ` `        ``return` `s ``/` `n ``+` `1``; ` `    ``else``: ` `        ``return` `s ``/` `n; ` ` `  `# Driver Code ` `n ``=` `5``; ` `s ``=` `11``; ` `print``(``int``(minimumNumbers(n, s))); ` ` `  `# This code is contributed  ` `# by Shivi_Aggarwal `

## C#

 `// C# program to find the minimum numbers ` `// required to get to S ` `using` `System; ` ` `  `class` `GFG { ` `     `  ` `  `// Function to find the minimum ` `// numbers required to get to S ` `static` `int` `minimumNumbers(``int` `n, ``int` `s) ` `{ ` `    ``if` `((s % n)>0) ` `        ``return` `s / n + 1; ` `    ``else` `        ``return` `s / n; ` `} ` ` `  `// Driver Code ` ` `  `    ``public` `static` `void` `Main () { ` `        ``int` `n = 5; ` `    ``int` `s = 11; ` `    ``Console.WriteLine(minimumNumbers(n, s)); ` `    ``} ` `} ` `// This code is contributed by shs.. `

## PHP

 ` `

Output:

```3
```

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Improved By : Shashank12, Shivi_Aggarwal

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