Given a binary string, count minimum number of subsequences to be removed to make it an empty string.
Input: str = "10001" Output: 1 Since the whole string is palindrome, we need only one removal. Input: str = "10001001" Output: 2 We can remove the middle 1 as first removal, after first removal string becomes 1000001 which is a palindrome.
Expected time complexity : O(n)
The problem is simple and can be solved easily using below two facts.
1) If given string is palindrome, we need only one removal.
2) Else we need two removals. Note that every binary string has all 1’s as a subsequence and all 0’s as another subsequence. We can remove any of the two subsequences to get a unary string. A unary string is always palindrome.
- Extend the above solution to count minimum number of subsequences to be removed to make it an empty string.
- What is the maximum count for ternary strings
This problem and solution are contributed by Hardik Gulati. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
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