Given a cyclic string str and two integers i and j, the task is to count the minimum number of steps required to move from str[i] to str[j]. A move is to reach any adjacent character in the string and the move is only counted if str[start] != start[end] where start is the starting index for the move and end is the ending (adjacent either on the left or on the right) index. Since, the given string is circular, str and str[n – 1] are adjacent to each other.
Input: str = “SSNSS”, i = 0, j = 3
From left to right : S -> S -> N -> S
From right to left : S -> S -> S
Input: str = “geeksforgeeks”, i = 0, j = 3
- Starting from index i start moving in the right direction till index j and for every character visited, if the current character is not equal to the previous character then increment steps1 = steps1 + 1.
- Similarly, starting from i start moving in the left direction till index 0 and for every character visited, if the current character is not equal to the previous character then increment steps2 = steps2 + 1. Once the index 0 is visited, start traversing from index n – 1 to j and increment step2 if str != str[n – 1].
- Print min(step1, step2) in the end.
Below is the implementation of the above approach:
- Count of cyclic permutations having XOR with other binary string as 0
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- Minimum cost to modify a string
- Lexicographically minimum string rotation | Set 1
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