# Minimum elements to be added in a range so that count of elements is divisible by K

Given three integer **K**, **L** and **R** (range **[L, R]**), the task is to find the minimum number of elements the range must be extended by so that the count of elements in the range is divisible by **K**.

**Examples:**

Input:K = 3, L = 10, R = 10

Output:2

Count of elements in L to R is 1.

So to make it divisible by 3 , increment it by 2.

Input:K = 5, L = 9, R = 12

Output:1

**Approach:**

- Count the total number of elements in the range and store it in a variable named
**count = R – L + 1**. - Now, minimum number of elements that need to be added to the range will be
**K – (count % K).**

Below is the implementation of the above approach:

## C++

`// C++ implementation of the approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `int` `minimumMoves(` `int` `k, ` `int` `l, ` `int` `r) ` `{ ` ` ` `// Total elements in the range ` ` ` `int` `count = r - l + 1; ` ` ` ` ` `// If total elements are already divisible by k ` ` ` `if` `(count % k == 0) ` ` ` `return` `0; ` ` ` ` ` `// Value that must be added to count ` ` ` `// in order to make it divisible by k ` ` ` `return` `(k - (count % k)); ` `} ` ` ` `// Driver Program to test above function ` `int` `main() ` `{ ` ` ` `int` `k = 3, l = 10, r = 10; ` ` ` `cout << minimumMoves(k, l, r); ` ` ` `return` `0; ` `} ` |

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## Java

`// Java implementation of the approach ` ` ` `import` `java.io.*; ` ` ` `class` `GFG { ` ` ` ` ` `static` `int` `minimumMoves(` `int` `k, ` `int` `l, ` `int` `r) ` `{ ` ` ` `// Total elements in the range ` ` ` `int` `count = r - l + ` `1` `; ` ` ` ` ` `// If total elements are already divisible by k ` ` ` `if` `(count % k == ` `0` `) ` ` ` `return` `0` `; ` ` ` ` ` `// Value that must be added to count ` ` ` `// in order to make it divisible by k ` ` ` `return` `(k - (count % k)); ` `} ` ` ` `// Driver Program to test above function ` ` ` `public` `static` `void` `main (String[] args) { ` ` ` `int` `k = ` `3` `, l = ` `10` `, r = ` `10` `; ` ` ` `System.out.print(minimumMoves(k, l, r)); ` ` ` `} ` `} ` `// This code is contributed ` `// by inder_verma.. ` |

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## Python3

`# Python 3 implementation of the approach ` ` ` `def` `minimumMoves(k, l, r): ` ` ` `# Total elements in the range ` ` ` `count ` `=` `r ` `-` `l ` `+` `1` ` ` ` ` `# If total elements are already divisible by k ` ` ` `if` `(count ` `%` `k ` `=` `=` `0` `): ` ` ` `return` `0` ` ` ` ` `# Value that must be added to count ` ` ` `# in order to make it divisible by k ` ` ` `return` `(k ` `-` `(count ` `%` `k)) ` ` ` `# Driver Program to test above function ` `if` `__name__ ` `=` `=` `'__main__'` `: ` ` ` `k ` `=` `3` ` ` `l ` `=` `10` ` ` `r ` `=` `10` ` ` `print` `(minimumMoves(k, l, r)) ` ` ` `# This code is contributed by ` `# Surendra_Gangwar ` |

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## C#

`// C# implementation of the approach ` `using` `System; ` ` ` `class` `GFG { ` ` ` ` ` ` ` `static` `int` `minimumMoves(` `int` `k, ` `int` `l, ` `int` `r) ` `{ ` ` ` `// Total elements in the range ` ` ` `int` `count = r - l + 1; ` ` ` ` ` `// If total elements are already divisible by k ` ` ` `if` `(count % k == 0) ` ` ` `return` `0; ` ` ` ` ` `// Value that must be added to count ` ` ` `// in order to make it divisible by k ` ` ` `return` `(k - (count % k)); ` `} ` ` ` `// Driver Program to test above function ` ` ` `public` `static` `void` `Main () { ` ` ` `int` `k = 3, l = 10, r = 10; ` ` ` `Console.WriteLine(minimumMoves(k, l, r)); ` ` ` `} ` `} ` `// This code is contributed ` `// by inder_verma.. ` |

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## PHP

`<?php ` `// PHP implementation of the approach ` ` ` `function` `minimumMoves(` `$k` `, ` `$l` `, ` `$r` `) ` `{ ` ` ` `// Total elements in the range ` ` ` `$count` `= ` `$r` `- ` `$l` `+ 1; ` ` ` ` ` `// If total elements are already divisible by k ` ` ` `if` `(` `$count` `% ` `$k` `== 0) ` ` ` `return` `0; ` ` ` ` ` `// Value that must be added to count ` ` ` `// in order to make it divisible by k ` ` ` `return` `(` `$k` `- (` `$count` `% ` `$k` `)); ` `} ` ` ` `// Driver Program to test above function ` ` ` ` ` `$k` `= 3; ` `$l` `= 10; ` `$r` `= 10; ` ` ` `echo` `minimumMoves(` `$k` `, ` `$l` `, ` `$r` `); ` `// This code is contributed ` `// by inder_verma.. ` ` ` ` ` `?> ` |

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**Output:**

2

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