Prerequisite : Minimax Algorithm in Game Theory

As seen in the above article, each leaf node had a value associated with it. We had stored this value in an array. But in the real world when we are creating a program to play Tic-Tac-Toe, Chess, Backgamon, etc. we need to implement a function that calculates the value of the board depending on the placement of pieces on the board. This function is often known as Evaluation Function. It is sometimes also called Heuristic Function.

The evaluation function is unique for every type of game. In this post, evaluation function for the game Tic-Tac-Toe is discussed. The basic idea behind the evaluation function is to give a high value for a board if **maximizer**‘s turn or a low value for the board if **minimizer**‘s turn.

For this scenario let us consider** X** as the **maximizer** and **O** as the **minimizer**.

Let us build our evaluation function :

- If X wins on the board we give it a positive value of +10.

- If O wins on the board we give it a negative value of -10.

- If no one has won or the game results in a draw then we give a value of +0.

We could have chosen any positive / negative value other than 10. For the sake of simplicity we chose 10 for the sake of simplicity we shall use lower case ‘x’ and lower case ‘o’ to represent the players and an underscore ‘_’ to represent a blank space on the board.

If we represent our board as a 3×3 2D character matrix, like char board[3][3]; then we have to check each row, each column and the diagonals to check if either of the players have gotten 3 in a row.

// C++ program to compute evaluation function for // Tic Tac Toe Game. #include<stdio.h> #include<algorithm> using namespace std; // Returns a value based on who is winning // b[3][3] is the Tic-Tac-Toe board int evaluate(char b[3][3]) { // Checking for Rows for X or O victory. for (int row = 0; row<3; row++) { if (b[row][0]==b[row][1] && b[row][1]==b[row][2]) { if (b[row][0]=='x') return +10; else if (b[row][0]=='o') return -10; } } // Checking for Columns for X or O victory. for (int col = 0; col<3; col++) { if (b[0][col]==b[1][col] && b[1][col]==b[2][col]) { if (b[0][col]=='x') return +10; else if (b[0][col]=='o') return -10; } } // Checking for Diagonals for X or O victory. if (b[0][0]==b[1][1] && b[1][1]==b[2][2]) { if (b[0][0]=='x') return +10; else if (b[0][0]=='o') return -10; } if (b[0][2]==b[1][1] && b[1][1]==b[2][0]) { if (b[0][2]=='x') return +10; else if (b[0][2]=='o') return -10; } // Else if none of them have won then return 0 return 0; } // Driver code int main() { char board[3][3] = { { 'x', '_', 'o'}, { '_', 'x', 'o'}, { '_', '_', 'x'} }; int value = evaluate(board); printf("The value of this board is %d\n", value); return 0; }

Output :

The value of this board is 10

The idea of this article is to understand how to write a simple evaluation function for the game Tic-Tac-Toe. In the next article we shall see how to combine this evaluation function with the minimax function. Stay Tuned.

This article is written by **Akshay L. Aradhya**. If you like GeeksforGeeks and would like to contribute, you can also write an article and mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above