Merge two sorted arrays
Given two sorted arrays, the task is to merge them in a sorted manner.
Examples:
Input: arr1[] = { 1, 3, 4, 5}, arr2[] = {2, 4, 6, 8}
Output: arr3[] = {1, 2, 3, 4, 4, 5, 6, 8}Input: arr1[] = { 5, 8, 9}, arr2[] = {4, 7, 8}
Output: arr3[] = {4, 5, 7, 8, 8, 9}
Naive Approach:
It is the brute force method to do the same. Take all the elements of arr1 and arr2 in arr3. Then simply sort the arr3.
The implementation of above approach is:
C++
// C++ program to merge two sorted arrays/ #include<bits/stdc++.h> using namespace std; void mergeArrays( int arr1[], int arr2[], int n1, int n2, int arr3[]) { int i = 0, j = 0, k = 0; // traverse the arr1 and insert its element in arr3 while (i < n1){ arr3[k++] = arr1[i++]; } // now traverse arr2 and insert in arr3 while (j < n2){ arr3[k++] = arr2[j++]; } // sort the whole array arr3 sort(arr3, arr3+n1+n2); } // Driver code int main() { int arr1[] = {1, 3, 5, 7}; int n1 = sizeof (arr1) / sizeof (arr1[0]); int arr2[] = {2, 4, 6, 8}; int n2 = sizeof (arr2) / sizeof (arr2[0]); int arr3[n1+n2]; mergeArrays(arr1, arr2, n1, n2, arr3); cout << "Array after merging" <<endl; for ( int i=0; i < n1+n2; i++) cout << arr3[i] << " " ; return 0; } |
Java
// Java program to merge two sorted arrays/ import java.util.*; public class GFG { // Driver code public static void main(String[] args) { int arr1[] = { 1 , 3 , 5 , 7 }; int n1 = arr1.length; int arr2[] = { 2 , 4 , 6 , 8 }; int n2 = arr2.length; int arr3[] = new int [n1 + n2]; mergeArrays(arr1, arr2, n1, n2, arr3); System.out.println( "Array after merging" ); for ( int i= 0 ; i < n1+n2; i++) System.out.print(arr3[i] + " " ); } public static void mergeArrays( int [] arr1, int [] arr2, int n1, int n2, int [] arr3){ int i = 0 ; int j = 0 ; int k = 0 ; // traverse the arr1 and insert its element in arr3 while (i < n1){ arr3[k++] = arr1[i++]; } // now traverse arr2 and insert in arr3 while (j < n2){ arr3[k++] = arr2[j++]; } // sort the whole array arr3 Arrays.sort(arr3); } } // This code is contributed by Tapesh(tapeshdua420) |
Python3
# Python program to merge two sorted arrays/ def mergeArrays(arr1, arr2, n1, n2, arr3): i = 0 j = 0 k = 0 # traverse the arr1 and insert its element in arr3 while (i < n1): arr3[k] = arr1[i] k + = 1 i + = 1 # now traverse arr2 and insert in arr3 while (j < n2): arr3[k] = arr2[j] k + = 1 j + = 1 # sort the whole array arr3 arr3.sort() # Driver code if __name__ = = '__main__' : arr1 = [ 1 , 3 , 5 , 7 ] n1 = len (arr1) arr2 = [ 2 , 4 , 6 , 8 ] n2 = len (arr2) arr3 = [ 0 for i in range (n1 + n2)] mergeArrays(arr1, arr2, n1, n2, arr3) print ( "Array after merging" ) for i in range (n1 + n2): print (arr3[i], end = " " ) # This code is contributed by Tapesh(tapeshdua420) |
C#
// C# program to merge two sorted arrays using System; using System.Collections.Generic; public class GFG { public static void mergeArrays( int [] arr1, int [] arr2, int n1, int n2, int [] arr3) { int i = 0; int j = 0; int k = 0; // traverse the arr1 and insert its element in arr3 while (i < n1) { arr3[k++] = arr1[i++]; } // now traverse arr2 and insert in arr3 while (j < n2) { arr3[k++] = arr2[j++]; } // sort the whole array arr3 Array.Sort(arr3); } public static void Main( string [] args) { int []arr1 = new int [] {1, 3, 5, 7}; int n1 = arr1.Length; int []arr2 = new int [] {2, 4, 6, 8}; int n2 = arr2.Length; int []arr3 = new int [n1 + n2]; mergeArrays(arr1, arr2, n1, n2, arr3); Console.WriteLine( "Array after merging" ); for ( int i = 0; i < n1 + n2; i++) Console.Write(arr3[i] + " " ); } } // This code is contributed by ajaymakavana. |
Javascript
// JavaScript program to merge two sorted arrays/ function mergeArrays(arr1, arr2, n1, n2, arr3) { var i = 0, j = 0, k = 0; // traverse the arr1 and insert its element in arr3 while (i < n1) { arr3[k++] = arr1[i++]; } // now traverse arr2 and insert in arr3 while (j < n2) { arr3[k++] = arr2[j++]; } // sort the whole array arr3 arr3.sort(); } var arr1 = [1, 3, 5, 7]; var n1 = arr1.length; var arr2 = [2, 4, 6, 8]; var n2 = arr2.length; var arr3 = new Array(n1 + n2); mergeArrays(arr1, arr2, n1, n2, arr3); console.log( "Array after merging" ); for ( var i = 0; i < n1 + n2; i++) process.stdout.write(arr3[i] + " " ); // This code is contributed by tapeshdua420. |
Array after merging 1 2 3 4 5 6 7 8
Time Complexity : O((m+n) log(m+n)) , the whole size of arr3 is m+n
Auxiliary Space: O(1), No extra space is used
Method 2 (O(n1 * n2) Time and O(n1+n2) Extra Space)
- Create an array arr3[] of size n1 + n2.
- Copy all n1 elements of arr1[] to arr3[]
- Traverse arr2[] and one by one insert elements (like insertion sort) of arr3[] to arr1[]. This step take O(n1 * n2) time.
We have discussed implementation of above method in Merge two sorted arrays with O(1) extra space
Method 3 (O(n1 + n2) Time and O(n1 + n2) Extra Space)
The idea is to use Merge function of Merge sort.
- Create an array arr3[] of size n1 + n2.
- Simultaneously traverse arr1[] and arr2[].
- Pick smaller of current elements in arr1[] and arr2[], copy this smaller element to next position in arr3[] and move ahead in arr3[] and the array whose element is picked.
- If there are remaining elements in arr1[] or arr2[], copy them also in arr3[].
Below is the illustration of the above approach:
Take two sorted arrays Array1 and Array2 and an Empty Array3 . Take three pointers ‘i’, ‘j’, and ‘k’ for comparisons, here ‘i’ pointer points towards 0th index of Array1, similarly ‘j’ and ‘k’ pointer point towards 0th index of Array2 and Array3
Initial Arrays
Step 1: Pick Smaller element which is 4 and insert in into Array3 and update the pointer ‘j ‘and ‘k’ after comparing ‘i’ and ‘j’.
Pick Smaller element which is 4
Step 2: Pick next smaller element which is 5 and insert in into Array3 and update the pointer ‘i’ and ‘k’ after comparing ‘i’ and ‘j’.
Pick next smaller element which is 5
Step 3: Pick next smaller element which is 7 and insert in into Array3 and update the pointer ‘j’ and ‘k ‘after comparing ‘i’ and ‘j’.
Pick next smaller element which is 7
Step 4: when ‘j’ pointer meets the length of Array2 then first while loop breaks and second while loop copies all elements from arr1 to arr3.
second while loop copies all elements from arr1 to arr3.
Step 5: Pick adjacent element from Array1 and insert in into Array3 and update the pointer i and k
Pick adjacent element from Array1 and insert in into Array3
Step 6: Pick remaining element from Array1 and insert in into Array3, when i pointer meets the length of Array1 that means k = n1+n2 and at last we have merge sorted Array3
ick remaining element from Array1 and insert in into Array3,
Below is the implementation of the above approach:
C++
// C++ program to merge two sorted arrays/ #include<iostream> using namespace std; // Merge arr1[0..n1-1] and arr2[0..n2-1] into // arr3[0..n1+n2-1] void mergeArrays( int arr1[], int arr2[], int n1, int n2, int arr3[]) { int i = 0, j = 0, k = 0; // Traverse both array while (i<n1 && j <n2) { // Check if current element of first // array is smaller than current element // of second array. If yes, store first // array element and increment first array // index. Otherwise do same with second array if (arr1[i] < arr2[j]) arr3[k++] = arr1[i++]; else arr3[k++] = arr2[j++]; } // Store remaining elements of first array while (i < n1) arr3[k++] = arr1[i++]; // Store remaining elements of second array while (j < n2) arr3[k++] = arr2[j++]; } // Driver code int main() { int arr1[] = {1, 3, 5, 7}; int n1 = sizeof (arr1) / sizeof (arr1[0]); int arr2[] = {2, 4, 6, 8}; int n2 = sizeof (arr2) / sizeof (arr2[0]); int arr3[n1+n2]; mergeArrays(arr1, arr2, n1, n2, arr3); cout << "Array after merging" <<endl; for ( int i=0; i < n1+n2; i++) cout << arr3[i] << " " ; return 0; } |
Java
// Java program to merge two sorted arrays import java.util.*; import java.lang.*; import java.io.*; class MergeTwoSorted { // Merge arr1[0..n1-1] and arr2[0..n2-1] // into arr3[0..n1+n2-1] public static void mergeArrays( int [] arr1, int [] arr2, int n1, int n2, int [] arr3) { int i = 0 , j = 0 , k = 0 ; // Traverse both array while (i<n1 && j <n2) { // Check if current element of first // array is smaller than current element // of second array. If yes, store first // array element and increment first array // index. Otherwise do same with second array if (arr1[i] < arr2[j]) arr3[k++] = arr1[i++]; else arr3[k++] = arr2[j++]; } // Store remaining elements of first array while (i < n1) arr3[k++] = arr1[i++]; // Store remaining elements of second array while (j < n2) arr3[k++] = arr2[j++]; } public static void main (String[] args) { int [] arr1 = { 1 , 3 , 5 , 7 }; int n1 = arr1.length; int [] arr2 = { 2 , 4 , 6 , 8 }; int n2 = arr2.length; int [] arr3 = new int [n1+n2]; mergeArrays(arr1, arr2, n1, n2, arr3); System.out.println( "Array after merging" ); for ( int i= 0 ; i < n1+n2; i++) System.out.print(arr3[i] + " " ); } } /* This code is contributed by Mr. Somesh Awasthi */ |
Python 3
# Python program to merge # two sorted arrays # Merge arr1[0..n1-1] and # arr2[0..n2-1] into # arr3[0..n1+n2-1] def mergeArrays(arr1, arr2, n1, n2): arr3 = [ None ] * (n1 + n2) i = 0 j = 0 k = 0 # Traverse both array while i < n1 and j < n2: # Check if current element # of first array is smaller # than current element of # second array. If yes, # store first array element # and increment first array # index. Otherwise do same # with second array if arr1[i] < arr2[j]: arr3[k] = arr1[i] k = k + 1 i = i + 1 else : arr3[k] = arr2[j] k = k + 1 j = j + 1 # Store remaining elements # of first array while i < n1: arr3[k] = arr1[i]; k = k + 1 i = i + 1 # Store remaining elements # of second array while j < n2: arr3[k] = arr2[j]; k = k + 1 j = j + 1 print ( "Array after merging" ) for i in range (n1 + n2): print ( str (arr3[i]), end = " " ) # Driver code arr1 = [ 1 , 3 , 5 , 7 ] n1 = len (arr1) arr2 = [ 2 , 4 , 6 , 8 ] n2 = len (arr2) mergeArrays(arr1, arr2, n1, n2); # This code is contributed # by ChitraNayal |
C#
// C# program to merge // two sorted arrays using System; class GFG { // Merge arr1[0..n1-1] and // arr2[0..n2-1] into // arr3[0..n1+n2-1] public static void mergeArrays( int [] arr1, int [] arr2, int n1, int n2, int [] arr3) { int i = 0, j = 0, k = 0; // Traverse both array while (i < n1 && j < n2) { // Check if current element // of first array is smaller // than current element // of second array. If yes, // store first array element // and increment first array // index. Otherwise do same // with second array if (arr1[i] < arr2[j]) arr3[k++] = arr1[i++]; else arr3[k++] = arr2[j++]; } // Store remaining // elements of first array while (i < n1) arr3[k++] = arr1[i++]; // Store remaining elements // of second array while (j < n2) arr3[k++] = arr2[j++]; } // Driver code public static void Main() { int [] arr1 = {1, 3, 5, 7}; int n1 = arr1.Length; int [] arr2 = {2, 4, 6, 8}; int n2 = arr2.Length; int [] arr3 = new int [n1+n2]; mergeArrays(arr1, arr2, n1, n2, arr3); Console.Write( "Array after merging\n" ); for ( int i = 0; i < n1 + n2; i++) Console.Write(arr3[i] + " " ); } } // This code is contributed // by ChitraNayal |
PHP
<?php // PHP program to merge // two sorted arrays // Merge $arr1[0..$n1-1] and // $arr2[0..$n2-1] into // $arr3[0..$n1+$n2-1] function mergeArrays(& $arr1 , & $arr2 , $n1 , $n2 , & $arr3 ) { $i = 0; $j = 0; $k = 0; // Traverse both array while ( $i < $n1 && $j < $n2 ) { // Check if current element // of first array is smaller // than current element of // second array. If yes, // store first array element // and increment first array // index. Otherwise do same // with second array if ( $arr1 [ $i ] < $arr2 [ $j ]) $arr3 [ $k ++] = $arr1 [ $i ++]; else $arr3 [ $k ++] = $arr2 [ $j ++]; } // Store remaining elements // of first array while ( $i < $n1 ) $arr3 [ $k ++] = $arr1 [ $i ++]; // Store remaining elements // of second array while ( $j < $n2 ) $arr3 [ $k ++] = $arr2 [ $j ++]; } // Driver code $arr1 = array (1, 3, 5, 7); $n1 = sizeof( $arr1 ); $arr2 = array (2, 4, 6, 8); $n2 = sizeof( $arr2 ); $arr3 [ $n1 + $n2 ] = array (); mergeArrays( $arr1 , $arr2 , $n1 , $n2 , $arr3 ); echo "Array after merging \n" ; for ( $i = 0; $i < $n1 + $n2 ; $i ++) echo $arr3 [ $i ] . " " ; // This code is contributed // by ChitraNayal ?> |
Javascript
<script> // javascript program to merge two sorted arrays // Merge arr1[0..n1-1] and arr2[0..n2-1] // into arr3[0..n1+n2-1] function mergeArrays(arr1, arr2 , n1 , n2, arr3) { var i = 0, j = 0, k = 0; // Traverse both array while (i < n1 && j < n2) { // Check if current element of first // array is smaller than current element // of second array. If yes, store first // array element and increment first array // index. Otherwise do same with second array if (arr1[i] < arr2[j]) arr3[k++] = arr1[i++]; else arr3[k++] = arr2[j++]; } // Store remaining elements of first array while (i < n1) arr3[k++] = arr1[i++]; // Store remaining elements of second array while (j < n2) arr3[k++] = arr2[j++]; } var arr1 = [ 1, 3, 5, 7 ]; var n1 = arr1.length; var arr2 = [ 2, 4, 6, 8 ]; var n2 = arr2.length; var arr3 = Array(n1 + n2).fill(0); mergeArrays(arr1, arr2, n1, n2, arr3); document.write( "Array after merging<br/>" ); for (i = 0; i < n1 + n2; i++) document.write(arr3[i] + " " ); // This code contributed by Rajput-Ji </script> |
Array after merging 1 2 3 4 5 6 7 8
Output:
Array after merging 1 2 3 4 5 6 7 8
Time Complexity : O(n1 + n2)
Auxiliary Space : O(n1 + n2)
Method 4: Using Maps (O(nlog(n) + mlog(m)) Time and O(N) Extra Space)
- Insert elements of both arrays in a map as keys.
- Print the keys of the map.
Below is the implementation of above approach.
CPP
// C++ program to merge two sorted arrays //using maps #include<bits/stdc++.h> using namespace std; // Function to merge arrays void mergeArrays( int a[], int b[], int n, int m) { // Declaring a map. // using map as a inbuilt tool // to store elements in sorted order. map< int , int > mp; // Inserting values to a map. for ( int i = 0; i < n; i++)mp[a[i]]++; for ( int i = 0;i < m;i++)mp[b[i]]++; // Printing keys of the map. for ( auto j: mp) { for ( int i=0; i<j.second;i++)cout<<j.first<< " " ; } } // Driver Code int main() { int a[] = {1, 3, 5, 7}, b[] = {2, 4, 6, 8}; int size = sizeof (a)/ sizeof ( int ); int size1 = sizeof (b)/ sizeof ( int ); // Function call mergeArrays(a, b, size, size1); return 0; } //This code is contributed by yashbeersingh42 |
Java
// Java program to merge two sorted arrays //using maps import java.io.*; import java.util.*; class GFG { // Function to merge arrays static void mergeArrays( int a[], int b[], int n, int m) { // Declaring a map. // using map as a inbuilt tool // to store elements in sorted order. Map<Integer,Boolean> mp = new TreeMap<Integer,Boolean>(); // Inserting values to a map. for ( int i = 0 ; i < n; i++) { mp.put(a[i], true ); } for ( int i = 0 ;i < m;i++) { mp.put(b[i], true ); } // Printing keys of the map. for (Map.Entry<Integer,Boolean> me : mp.entrySet()) { System.out.print(me.getKey() + " " ); } } // Driver Code public static void main (String[] args) { int a[] = { 1 , 3 , 5 , 7 }, b[] = { 2 , 4 , 6 , 8 }; int size = a.length; int size1 = b.length; // Function call mergeArrays(a, b, size, size1); } } // This code is contributed by rag2127 |
Python3
# Python program to merge two sorted arrays # using maps import bisect # Function to merge arrays def mergeArrays(a, b, n, m): # Declaring a map. # using map as a inbuilt tool # to store elements in sorted order. mp = [] # Inserting values to a map. for i in range (n): bisect.insort(mp, a[i]) for i in range (m): bisect.insort(mp, b[i]) # Printing keys of the map. for i in mp: print (i,end = ' ' ) # Driver code arr1 = [ 1 , 3 , 5 , 7 ] arr2 = [ 2 , 4 , 6 , 8 ] size = len (arr1) size1 = len (arr2) # Function call mergeArrays(arr1, arr2, size, size1) # This code is contributed by Pushpesh Raj |
C#
// C# program to merge two sorted arrays //using maps using System; using System.Collections.Generic; public class GFG { // Function to merge arrays static void mergeArrays( int []a, int []b, int n, int m) { // Declaring a map. // using map as a inbuilt tool // to store elements in sorted order. SortedDictionary< int , Boolean> mp = new SortedDictionary< int , Boolean>(); // Inserting values to a map. for ( int i = 0; i < n; i++) { mp.Add(a[i], true ); } for ( int i = 0; i < m; i++) { mp.Add(b[i], true ); } // Printing keys of the map. foreach (KeyValuePair< int , Boolean> me in mp) { Console.Write(me.Key + " " ); } } // Driver Code public static void Main(String[] args) { int []a = { 1, 3, 5, 7 }; int []b = { 2, 4, 6, 8 }; int size = a.Length; int size1 = b.Length; // Function call mergeArrays(a, b, size, size1); } } // This code is contributed by gauravrajput1 |
Javascript
<script> // javascript program to merge two sorted arrays //using maps // Function to merge arrays function mergeArrays(a , b , n , m) { // Declaring a map. // using map as a inbuilt tool // to store elements in sorted order. var mp = new Map(); // Inserting values to a map. for (i = 0; i < n; i++) { mp.set(a[i], true ); } for (i = 0; i < m; i++) { mp.set(b[i], true ); } var a = []; // Printing keys of the map. for ( me of mp.keys()) { a.push(me); } a.sort(); for ( me of a) { document.write(me + " " ); } } // Driver Code var a = [ 1, 3, 5, 7 ], b = [ 2, 4, 6, 8 ]; var size = a.length; var size1 = b.length; // Function call mergeArrays(a, b, size, size1); // This code is contributed by gauravrajput1 </script> |
1 2 3 4 5 6 7 8
Time Complexity: O( nlog(n) + mlog(m) )
Auxiliary Space: O(N)
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