Skip to content
Related Articles

Related Articles

Improve Article

Media.net Interview Experience 2021

  • Difficulty Level : Expert
  • Last Updated : 06 Aug, 2021

Online Assessment:

  1. Given a tree rooted at 1 with n nodes, q queries are given. In each query, d, e are given as input. You need to find the maximum value of e^x where x is one of the ancestors of d or d itself in the tree.
    n<=10^5
    q<=3*10^5
    e<=3*10^5
    1<=d<=n
  2. A bus stops at n bus stops, each bus stop having a[i] people. The bus needs to take in all the people on the bus. People from 1 bus stop get down before the next bus stop arrives. They use a resizing tech which allows the bus to be resized to whatever capacity they want. This action can be done only b times at max. The uselessness of the bus is the summation of a total number of unoccupied seats across n stops. Find the minimum uselessness the bus can achieve if the resizing tech is used optimally. 1<=a[i]<=10^6, 1<=b<=n<=400
    Ex 1:
    a = [10 20] b = 0
    Ans:10

    Explanation – the resizing tech cannot be applied. hence the capacity of the bus is 20 initially. in the first stop, 20-10 seats were unused. in the second stop 20 – 20 seats are unused. Total unused seats = 10

    Hey geek! It's time to become a success story instead of reading them. Check out our most renowned DSA Self Paced Course, now at a student-friendly price and become industry ready. And if you are looking for a more complete interview preparation resource, check out Complete Interview Preparation Course that will prepare you for the SDE role of your dreams!

    Feeling prepared enough for your interview? Test your skills with our Test Series that will help you prepare for top companies like Amazon, Microsft, TCS, Wipro, Google and many more!

    Ex 2:
    a = [10 20 30] b = 1
    Ans: 10

    Explanation – the resizing tech can be applied only once. The capacity of the bus is 10 initially. in the first stop 10-10 seats unused = 0. in the second stop, the tech is used to resize to 30. 30 – 20 seats unused.



    In the third stop,  30-30 seats unused

    Total unused seats = 10.

  3. You will be given n points in a 2D plane which represents the corona orange zone. On the i-th day, Corona will spread to all the locations which are within i euclidean distance from each Corona orange zone. A zone will become red, if it coincides with atleast ‘x’ orange zones. Given the n  pairs and x, find the day in which the first red zone occurs.
    1<=n<=100, 1<=b<=n, 
    for each point, 
    1<=x<=10^9, 1<=y<=10^9
    Example-
    (9,4),(10,3) , x=2.
    Ans : 1

    In point (9,3) both the zones would have been affected after day 1. Hence it will become a red zone after day 1.

Interview Round 1: I was asked to introduce myself. After a short introduction, I was directly given a problem. The problem is as follows:

  1. You are given 4 strings w,x,y,z. You can permute each of the strings however you want. You have to fix 1 permutation for each of the 4 strings such that when you add all the 4 strings into a trie, the number of nodes created in the trie is minimized.
    Example-
    w = abaa
    x = aaaa
    y = acca
    z = abca
    For permutaion:
    w = abaa
    x = aaaa
    y = acca
    z = abca

    Number of nodes in Trie – 1 (number of new nodes for first character of all strings) + 3(for second character ) + 4(for third character ) + 4(for fourth character ) = 12

    minimum number of trie nodes when:

    w = aaab
    x = aaaa
    y = aacc
    z = aacd
    Number of nodes : 
    1 + 1 + 2 + 4 = 8

    I gave a O(2^ (number of words (4 in this case)) * number of characters(26 in this case)) using bitmasks. The interviewer was convinced.

Interview Round 2: There was a small introduction. Then the interviewer directly jumped into a problem.

  1. You are given a 2D array of integers with dimension n X m and a value ‘k’. Find if there exists a square submatrix whose sum is equal to k.
    Example-
    n = 3, m = 3, k = 10
    1 2 3
    2 3 4
    3 2 6
    Output: true

    Explanation: The square starting from (1,0) to (2,1) (Zero based indexing) has a sum 2 + 3 + 2 + 3 = 10 which is equal to k.

    I first gave O(m*n*min(m,n)) solution using DP and optimised it O(m*n*log(min(n,m))) using binary search. But the expected solution was O(m*n) using 2 pointers.

My Personal Notes arrow_drop_up
Recommended Articles
Page :