We are given a number n, we need to find the maximum sum possible with the help of following function:
F(n) = max( (F(n/2) + F(n/3) + F(n/4) + F(n/5)), n). To calculate F(n, ) we may either have n as our result or we can further break n into four part as in given function definition. This can be done as much time as we can. Find the maximum possible sum you can get from a given N. Note : 1 can not be break further so F(1) = 1 as a base case.
Input : n = 10 Output : MaxSum = 12 Explanation: f(10) = f(10/2) + f(10/3) + f(10/4) + f(10/5) = f(5) + f(3) + f(2) + f(2) = 12 5, 3 and 2 cannot be further divided. Input : n = 2 Output : MaxSum = 2
Approach : This problem can be solve with recursive approach but that will cost us a high complexity because of its overlapping sub problems. So we apply dynamic programming concept to solve this question in bottom up manner as:
MaxSum = 106
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Improved By : jit_t