Maximum sum of values of nodes among all connected components of an undirected graph

Given an undirected graph with V vertices and E edges. Every node has been assigned a given value. The task is to find the connected chain with the maximum sum of of values among all the connected components in the graph.
Examples:

Input: V = 7, E = 4
Values = {10, 25, 5, 15, 5, 20, 0}

Output : Max Sum value = 35
Explanation:
Component {1, 2} – Value {10, 25}: sumValue = 10 + 25 = 35
Component {3, 4, 5} – Value {5, 15, 5}: sumValue = 5 + 15 + 5 = 25
Component {6, 7} – Value {20, 0}: sumValue = 20 + 0 = 20
Max Sum value chain is {1, 2} with values {10, 25}, hence 35 is answer.
Input: V = 10, E = 6
Values = {5, 10, 15, 20, 25, 30, 35, 40, 45, 50}

Output : Max Sum value = 105

Approach: The idea is to use the Depth First Search traversal method to keep a track of all the connected components. A temporary variable is used to sum up all the values of the individual values of the connected chains. At each traversal of a connected component, the heaviest value till now is compared with the current value and updated accordingly. After all connected components have been traversed, the maximum among all will the answer.
Below is the implementation of the above approach:

C++

// C++ program to find Maximum sum of values 
// of nodes among all connected 
// components of an undirected graph 
#include <bits/stdc++.h> 
using namespace std; 
  
// Function to implement DFS 
void depthFirst(int v, vector<int> graph[], 
                vector<bool>& visited, 
                int& sum, 
                vector<int> values) 
{ 
    // Marking the visited vertex as true 
    visited[v] = true; 
  
    // Updating the value of connection 
    sum += values[v - 1]; 
  
    // Traverse for all adjacent nodes 
    for (auto i : graph[v]) { 
  
        if (visited[i] == false) { 
  
            // Recursive call to the DFS algorithm 
            depthFirst(i, graph, visited, 
                       sum, values); 
        } 
    } 
} 
  
void maximumSumOfValues(vector<int> graph[], 
                        int vertices, vector<int> values) 
{ 
    // Initializing boolean array to mark visited vertices 
    vector<bool> visited(values.size() + 1, false); 
  
    // maxChain stores the maximum chain size 
    int maxValueSum = INT_MIN; 
  
    // Following loop invokes DFS algorithm 
    for (int i = 1; i <= vertices; i++) { 
        if (visited[i] == false) { 
  
            // Variable to hold temporary values 
            int sum = 0; 
  
            // DFS algorithm 
            depthFirst(i, graph, visited, 
                       sum, values); 
  
            // Conditional to update max value 
            if (sum > maxValueSum) { 
                maxValueSum = sum; 
            } 
        } 
    } 
  
    // Printing the heaviest chain value 
    cout << "Max Sum value = "; 
    cout << maxValueSum << "\n"; 
} 
  
// Driver function to test above function 
int main() 
{ 
    // Initializing graph in the form of adjacency list 
    vector<int> graph[1001]; 
  
    // Defining the number of edges and vertices 
    int E = 4, V = 7; 
  
    // Assigning the values for each 
    // vertex of the undirected graph 
    vector<int> values; 
    values.push_back(10); 
    values.push_back(25); 
    values.push_back(5); 
    values.push_back(15); 
    values.push_back(5); 
    values.push_back(20); 
    values.push_back(0); 
  
    // Constructing the undirected graph 
    graph[1].push_back(2); 
    graph[2].push_back(1); 
    graph[3].push_back(4); 
    graph[4].push_back(3); 
    graph[3].push_back(5); 
    graph[5].push_back(3); 
    graph[6].push_back(7); 
    graph[7].push_back(6); 
  
    maximumSumOfValues(graph, V, values); 
    return 0; 
} 

Java

// Java program to find Maximum sum of 
// values of nodes among all connected 
// components of an undirected graph 
import java.util.*; 
  
class GFG{ 
      
static int sum; 
  
// Function to implement DFS 
static void depthFirst(int v, 
                       Vector<Integer> graph[], 
                       boolean []visited, 
                       Vector<Integer> values) 
{ 
      
    // Marking the visited vertex as true 
    visited[v] = true; 
  
    // Updating the value of connection 
    sum += values.get(v - 1); 
  
    // Traverse for all adjacent nodes 
    for(int i : graph[v])  
    { 
        if (visited[i] == false) 
        { 
              
            // Recursive call to the DFS algorithm 
            depthFirst(i, graph, visited, values); 
        } 
    } 
} 
  
static void maximumSumOfValues(Vector<Integer> graph[], 
                               int vertices,  
                               Vector<Integer> values) 
{ 
      
    // Initializing boolean array to 
    // mark visited vertices 
    boolean []visited = new boolean[values.size() + 1]; 
  
    // maxChain stores the maximum chain size 
    int maxValueSum = Integer.MIN_VALUE; 
  
    // Following loop invokes DFS algorithm 
    for(int i = 1; i <= vertices; i++)  
    { 
        if (visited[i] == false) 
        { 
              
            // Variable to hold temporary values 
            sum = 0; 
  
            // DFS algorithm 
            depthFirst(i, graph, visited, values); 
  
            // Conditional to update max value 
            if (sum > maxValueSum) 
            { 
                maxValueSum = sum; 
            } 
        } 
    } 
      
    // Printing the heaviest chain value 
    System.out.print("Max Sum value = "); 
    System.out.print(maxValueSum + "\n"); 
} 
  
// Driver code 
public static void main(String[] args) 
{ 
      
    // Initializing graph in the form 
    // of adjacency list 
    @SuppressWarnings("unchecked") 
    Vector<Integer> []graph = new Vector[1001]; 
      
    for(int i = 0; i < graph.length; i++) 
        graph[i] = new Vector<Integer>(); 
          
    // Defining the number of edges and vertices 
    int E = 4, V = 7; 
  
    // Assigning the values for each 
    // vertex of the undirected graph 
    Vector<Integer> values = new Vector<Integer>(); 
    values.add(10); 
    values.add(25); 
    values.add(5); 
    values.add(15); 
    values.add(5); 
    values.add(20); 
    values.add(0); 
  
    // Constructing the undirected graph 
    graph[1].add(2); 
    graph[2].add(1); 
    graph[3].add(4); 
    graph[4].add(3); 
    graph[3].add(5); 
    graph[5].add(3); 
    graph[6].add(7); 
    graph[7].add(6); 
  
    maximumSumOfValues(graph, V, values); 
} 
} 
  
// This code is contributed by Rajput-Ji 

Output:

Max Sum value = 35

Time Complexity: O(E + V)

My Personal Notes

C++

Java

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