Maximum length substring having all same characters after k changes

We have a string of length n, which consist only UPPER and LOWER CASE characters and we have a number k (always less than n and greater than 0). We can make at most k changes in our string such that we can get a sub-string of maximum length which have all same characters.

Examples:

n = length of string
k = changes you can make
Input : n = 5 k = 2
        str = ABABA
Output : maximum length = 5
which will be (AAAAA)

Input : n = 6 k = 4
       str = HHHHHH
Output : maximum length=6
which will be(HHHHHH)

Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.

We check for each character of English alphabet (both upper and lower cases one by one). We are basically looking for maximum length of sub-string that can be formed by each character and whichever character will form the sub-string of maximum length then that length will be our answer.

We check for maximum length of sub-string that can be formed by every character in a set of 52 characters (From ‘A’ to ‘Z’ and from ‘a’ to ‘z’).
For doing this we traverse whole string and whenever we find a different character, we increase the count.
If count becomes greater than k (at right index), we again start from 0th index and if we found different character we will decrease the count.
When count will be equal to k (at left index) then at that point the length will be rightIndex-leftIndex+1.
We repeat this process until we reach at the end of string and at that point we will return the maximum length.
We do this for all characters and finally return the maximum length.

C++

// C++ program to find maximum length equal 
// character string with k changes 
#include <iostream> 
using namespace std; 
  
// function to find the maximum length of  
// substring having character ch 
int findLen(string& A, int n, int k, char ch) 
{ 
    int maxlen = 1; 
    int cnt = 0; 
    int l = 0, r = 0; 
      
    // traverse the whole string 
    while (r < n) { 
      
        /* if character is not same as ch 
           increase count */
        if (A[r] != ch) 
            ++cnt; 
  
        /* While  count > k  traverse the string 
           again until count becomes less than k  
           and decrease the count when characters  
           are not same */
        while (cnt > k) { 
            if (A[l] != ch) 
                --cnt; 
            ++l; 
        } 
  
        /* length of substring will be rightIndex - 
           leftIndex + 1. Compare this with the maximum 
           length and return maximum length */
        maxlen = max(maxlen, r - l + 1); 
        ++r; 
    } 
    return maxlen; 
} 
  
// function which returns maximum length of substring 
int answer(string& A, int n, int k) 
{ 
    int maxlen = 1; 
    for (int i = 0; i < 26; ++i) { 
        maxlen = max(maxlen, findLen(A, n, k, i+'A')); 
        maxlen = max(maxlen, findLen(A, n, k, i+'a')); 
    } 
    return maxlen; 
} 
  
// Driver code 
int main() 
{ 
    int n = 5, k = 2; 
    string A = "ABABA"; 
    cout << "Maximum length = " << answer(A, n, k) << endl; 
  
    n = 6, k = 4; 
    string B = "HHHHHH"; 
    cout << "Maximum length = " << answer(B, n, k) << endl; 
    return 0; 
} 

Java

// Java program to find maximum length equal 
// character string with k changes 
  
public class GFG  
{ 
    // method to find the maximum length of  
    // substring having character ch 
    static int findLen(String A, int n, int k, char ch) 
    { 
        int maxlen = 1; 
        int cnt = 0; 
        int l = 0, r = 0; 
           
        // traverse the whole string 
        while (r < n) { 
           
            /* if character is not same as ch 
               increase count */
            if (A.charAt(r) != ch) 
                ++cnt; 
       
            /* While  count > k  traverse the string 
               again until count becomes less than k  
               and decrease the count when characters  
               are not same */
            while (cnt > k) { 
                if (A.charAt(l) != ch) 
                    --cnt; 
                ++l; 
            } 
       
            /* length of substring will be rightIndex - 
               leftIndex + 1. Compare this with the maximum 
               length and return maximum length */
            maxlen = Math.max(maxlen, r - l + 1); 
            ++r; 
        } 
        return maxlen; 
    } 
       
    // method which returns maximum length of substring 
    static int answer(String A, int n, int k) 
    { 
        int maxlen = 1; 
        for (int i = 0; i < 26; ++i) { 
            maxlen = Math.max(maxlen, findLen(A, n, k, (char) (i+'A'))); 
            maxlen = Math.max(maxlen, findLen(A, n, k, (char) (i+'a'))); 
        } 
        return maxlen; 
    } 
      
    // Driver Method 
    public static void main(String[] args) 
    { 
        int n = 5, k = 2; 
        String A = "ABABA"; 
        System.out.println("Maximum length = " + answer(A, n, k)); 
       
        n = 6; k = 4; 
        String B = "HHHHHH"; 
        System.out.println("Maximum length = " + answer(B, n, k)); 
    } 
} 

Python3

# Python3 program to find maximum length  
# equal character string with k changes 
  
# function to find the maximum length of 
# substring having character ch 
def findLen(A, n, k, ch): 
    maxlen = 1
    cnt = 0
    l = 0
    r = 0
  
    # traverse the whole string 
    while r < n: 
  
        # if character is not same as ch 
        # increase count 
        if A[r] != ch: 
            cnt += 1
  
        # While count > k traverse the string 
        # again until count becomes less than k 
        # and decrease the count when characters 
        # are not same 
        while cnt > k: 
            if A[l] != ch: 
                cnt -= 1
            l += 1
  
        # length of substring will be rightIndex - 
        # leftIndex + 1. Compare this with the  
        # maximum length and return maximum length 
        maxlen = max(maxlen, r - l + 1) 
        r += 1
  
    return maxlen 
  
# function which returns 
# maximum length of substring 
def answer(A, n, k): 
    maxlen = 1
    for i in range(26): 
        maxlen = max(maxlen, findLen(A, n, k,  
                             chr(i + ord('A')))) 
        maxlen = max(maxlen, findLen(A, n, k,  
                             chr(i + ord('a')))) 
  
    return maxlen 
  
# Driver Code 
if __name__ == "__main__": 
    n = 5
    k = 2
    A = "ABABA"
    print("Maximum length =", 
             answer(A, n, k)) 
  
    n = 6
    k = 4
    B = "HHHHHH"
    print("Maximum length =",  
             answer(B, n, k)) 
  
# This code is contributed by 
# sanjeev2552 

C#

// C# program to find maximum length equal  
// character string with k changes  
using System; 
  
class GFG 
{ 
      
    // method to find the maximum length of  
    // substring having character ch  
    public static int findLen(string A, int n, 
                               int k, char ch) 
    { 
        int maxlen = 1; 
        int cnt = 0; 
        int l = 0, r = 0; 
  
        // traverse the whole string  
        while (r < n) 
        { 
  
            // if character is  
            // not same as ch  
            // increase count  
            if (A[r] != ch) 
            { 
                ++cnt; 
            } 
  
            // While count > k traverse  
            // the string again until 
            // count becomes less than 
            // k and decrease the  
            // count when characters  
            // are not same 
            while (cnt > k) 
            { 
                if (A[l] != ch) 
                { 
                    --cnt; 
                } 
                ++l; 
            } 
  
            // length of substring  
            // will be rightIndex -  
            // leftIndex + 1.  
            // Compare this with the maximum  
            // length and return maximum length 
            maxlen = Math.Max(maxlen, r - l + 1); 
            ++r; 
        } 
        return maxlen; 
    } 
  
    // method which returns  
    // maximum length of substring  
    public static int answer(string A, int n, int k) 
    { 
        int maxlen = 1; 
        for (int i = 0; i < 26; ++i) 
        { 
            maxlen = Math.Max(maxlen,  
              findLen(A, n, k, (char)(i + 'A'))); 
                
            maxlen = Math.Max(maxlen,  
              findLen(A, n, k, (char)(i + 'a'))); 
        } 
        return maxlen; 
    } 
  
// Driver Method  
public static void Main(string[] args) 
{ 
    int n = 5, k = 2; 
    string A = "ABABA"; 
    Console.WriteLine("Maximum length = " 
                      + answer(A, n, k)); 
  
    n = 6; 
    k = 4; 
    string B = "HHHHHH"; 
    Console.WriteLine("Maximum length = " 
                      + answer(B, n, k)); 
} 
} 
  
// This code is contributed by Shrikant13 

PHP

<?php  
// PHP program to find maximum length equal 
// character string with k changes 
  
// function to find the maximum length  
// of substring having character ch 
function findLen($A, $n, $k, $ch) 
{ 
    $maxlen = 1; $cnt = 0; 
    $l = 0; $r = 0; 
      
    // traverse the whole string 
    while ($r < $n)  
    { 
      
        /* if character is not same as  
        ch increase count */
        if ($A[$r] != $ch) 
            ++$cnt; 
  
        /* While count > k traverse the string 
        again until count becomes less than k  
        and decrease the count when characters  
        are not same */
        while ($cnt > $k)  
        { 
            if ($A[$l] != $ch) 
                --$cnt; 
            ++$l; 
        } 
  
        /* length of substring will be rightIndex - 
        leftIndex + 1. Compare this with the maximum 
        length and return maximum length */
        $maxlen = max($maxlen, $r - $l + 1); 
        ++$r; 
    } 
    return $maxlen; 
} 
  
// function which returns maximum 
// length of substring 
function answer($A, $n, $k) 
{ 
    $maxlen = 1; 
    for ($i = 0; $i < 26; ++$i)  
    { 
        $maxlen = max($maxlen,  
                      findLen($A, $n, $k, $i + 'A')); 
        $maxlen = max($maxlen,  
                      findLen($A, $n, $k, $i + 'a')); 
    } 
    return $maxlen; 
} 
  
// Driver code 
$n = 5; $k = 2; $A = "ABABA"; 
echo "Maximum length = " . answer($A, $n, $k) . "\n"; 
  
$n = 6; $k = 4; $B = "HHHHHH"; 
echo "Maximum length = " . answer($B, $n, $k) . "\n"; 
   
// This code is contributed by ita_c 
?> 

Output:

Maximum length = 5
Maximum length = 6

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My Personal Notes

Recommended: Please solve it on “PRACTICE ” first, before moving on to the solution.

C++

Java

Python3

C#

PHP

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