Maximum element between two nodes of BST
Given an array of N elements and two integers A, B which belong to the given array. Create a Binary Search Tree by inserting elements from arr[0] to arr[n-1]. The task is to find the maximum element in the path from A to B.
Examples :
Input : arr[] = { 18, 36, 9, 6, 12, 10, 1, 8 }, a = 1, b = 10. Output : 12
Path from 1 to 10 contains { 1, 6, 9, 12, 10 }. The maximum element is 12.
The idea is to find Lowest Common Ancestor of node ‘a’ and node ‘b’. Then search maximum node between LCA and ‘a’, and also find the maximum node between LCA and ‘b’. The answer will be maximum node of two.
Implementation:
C++
// C++ program to find maximum element in the path // between two Nodes of Binary Search Tree. #include <bits/stdc++.h> using namespace std; struct Node { struct Node *left, *right; int data; }; // Create and return a pointer of new Node. Node *createNode( int x) { Node *p = new Node; p -> data = x; p -> left = p -> right = NULL; return p; } // Insert a new Node in Binary Search Tree. void insertNode( struct Node *root, int x) { Node *p = root, *q = NULL; while (p != NULL) { q = p; if (p -> data < x) p = p -> right; else p = p -> left; } if (q == NULL) p = createNode(x); else { if (q -> data < x) q -> right = createNode(x); else q -> left = createNode(x); } } // Return the maximum element between a Node // and its given ancestor. int maxelpath(Node *q, int x) { Node *p = q; int mx = INT_MIN; // Traversing the path between ancestor and // Node and finding maximum element. while (p -> data != x) { if (p -> data > x) { mx = max(mx, p -> data); p = p -> left; } else { mx = max(mx, p -> data); p = p -> right; } } return max(mx, x); } // Return maximum element in the path between // two given Node of BST. int maximumElement( struct Node *root, int x, int y) { Node *p = root; // Finding the LCA of Node x and Node y while ((x < p -> data && y < p -> data) || (x > p -> data && y > p -> data)) { // Checking if both the Node lie on the // left side of the parent p. if (x < p -> data && y < p -> data) p = p -> left; // Checking if both the Node lie on the // right side of the parent p. else if (x > p -> data && y > p -> data) p = p -> right; } // Return the maximum of maximum elements occur // in path from ancestor to both Node. return max(maxelpath(p, x), maxelpath(p, y)); } // Driver Code int main() { int arr[] = { 18, 36, 9, 6, 12, 10, 1, 8 }; int a = 1, b = 10; int n = sizeof (arr) / sizeof (arr[0]); // Creating the root of Binary Search Tree struct Node *root = createNode(arr[0]); // Inserting Nodes in Binary Search Tree for ( int i = 1; i < n; i++) insertNode(root, arr[i]); cout << maximumElement(root, a, b) << endl; return 0; } |
Java
// Java program to find maximum element in the path // between two Nodes of Binary Search Tree. class Solution { static class Node { Node left, right; int data; } // Create and return a pointer of new Node. static Node createNode( int x) { Node p = new Node(); p . data = x; p . left = p . right = null ; return p; } // Insert a new Node in Binary Search Tree. static void insertNode( Node root, int x) { Node p = root, q = null ; while (p != null ) { q = p; if (p . data < x) p = p . right; else p = p . left; } if (q == null ) p = createNode(x); else { if (q . data < x) q . right = createNode(x); else q . left = createNode(x); } } // Return the maximum element between a Node // and its given ancestor. static int maxelpath(Node q, int x) { Node p = q; int mx = - 1 ; // Traversing the path between ancestor and // Node and finding maximum element. while (p . data != x) { if (p . data > x) { mx = Math.max(mx, p . data); p = p . left; } else { mx = Math.max(mx, p . data); p = p . right; } } return Math.max(mx, x); } // Return maximum element in the path between // two given Node of BST. static int maximumElement( Node root, int x, int y) { Node p = root; // Finding the LCA of Node x and Node y while ((x < p . data && y < p . data) || (x > p . data && y > p . data)) { // Checking if both the Node lie on the // left side of the parent p. if (x < p . data && y < p . data) p = p . left; // Checking if both the Node lie on the // right side of the parent p. else if (x > p . data && y > p . data) p = p . right; } // Return the maximum of maximum elements occur // in path from ancestor to both Node. return Math.max(maxelpath(p, x), maxelpath(p, y)); } // Driver Code public static void main(String args[]) { int arr[] = { 18 , 36 , 9 , 6 , 12 , 10 , 1 , 8 }; int a = 1 , b = 10 ; int n =arr.length; // Creating the root of Binary Search Tree Node root = createNode(arr[ 0 ]); // Inserting Nodes in Binary Search Tree for ( int i = 1 ; i < n; i++) insertNode(root, arr[i]); System.out.println( maximumElement(root, a, b) ); } } //contributed by Arnab Kundu |
Python3
# Python 3 program to find maximum element # in the path between two Nodes of Binary # Search Tree. # Create and return a pointer of new Node. class createNode: # Constructor to create a new node def __init__( self , data): self .data = data self .left = None self .right = None # Insert a new Node in Binary Search Tree. def insertNode(root, x): p, q = root, None while p ! = None : q = p if p.data < x: p = p.right else : p = p.left if q = = None : p = createNode(x) else : if q.data < x: q.right = createNode(x) else : q.left = createNode(x) # Return the maximum element between a # Node and its given ancestor. def maxelpath(q, x): p = q mx = - 999999999999 # Traversing the path between ancestor # and Node and finding maximum element. while p.data ! = x: if p.data > x: mx = max (mx, p.data) p = p.left else : mx = max (mx, p.data) p = p.right return max (mx, x) # Return maximum element in the path # between two given Node of BST. def maximumElement(root, x, y): p = root # Finding the LCA of Node x and Node y while ((x < p.data and y < p.data) or (x > p.data and y > p.data)): # Checking if both the Node lie on # the left side of the parent p. if x < p.data and y < p.data: p = p.left # Checking if both the Node lie on # the right side of the parent p. elif x > p.data and y > p.data: p = p.right # Return the maximum of maximum elements # occur in path from ancestor to both Node. return max (maxelpath(p, x), maxelpath(p, y)) # Driver Code if __name__ = = '__main__' : arr = [ 18 , 36 , 9 , 6 , 12 , 10 , 1 , 8 ] a, b = 1 , 10 n = len (arr) # Creating the root of Binary Search Tree root = createNode(arr[ 0 ]) # Inserting Nodes in Binary Search Tree for i in range ( 1 ,n): insertNode(root, arr[i]) print (maximumElement(root, a, b)) # This code is contributed by PranchalK |
C#
using System; // C# program to find maximum element in the path // between two Nodes of Binary Search Tree. public class Solution { public class Node { public Node left, right; public int data; } // Create and return a pointer of new Node. public static Node createNode( int x) { Node p = new Node(); p.data = x; p.left = p.right = null ; return p; } // Insert a new Node in Binary Search Tree. public static void insertNode(Node root, int x) { Node p = root, q = null ; while (p != null ) { q = p; if (p.data < x) { p = p.right; } else { p = p.left; } } if (q == null ) { p = createNode(x); } else { if (q.data < x) { q.right = createNode(x); } else { q.left = createNode(x); } } } // Return the maximum element between a Node // and its given ancestor. public static int maxelpath(Node q, int x) { Node p = q; int mx = -1; // Traversing the path between ancestor and // Node and finding maximum element. while (p.data != x) { if (p.data > x) { mx = Math.Max(mx, p.data); p = p.left; } else { mx = Math.Max(mx, p.data); p = p.right; } } return Math.Max(mx, x); } // Return maximum element in the path between // two given Node of BST. public static int maximumElement(Node root, int x, int y) { Node p = root; // Finding the LCA of Node x and Node y while ((x < p.data && y < p.data) || (x > p.data && y > p.data)) { // Checking if both the Node lie on the // left side of the parent p. if (x < p.data && y < p.data) { p = p.left; } // Checking if both the Node lie on the // right side of the parent p. else if (x > p.data && y > p.data) { p = p.right; } } // Return the maximum of maximum elements occur // in path from ancestor to both Node. return Math.Max(maxelpath(p, x), maxelpath(p, y)); } // Driver Code public static void Main( string [] args) { int [] arr = new int [] {18, 36, 9, 6, 12, 10, 1, 8}; int a = 1, b = 10; int n = arr.Length; // Creating the root of Binary Search Tree Node root = createNode(arr[0]); // Inserting Nodes in Binary Search Tree for ( int i = 1; i < n; i++) { insertNode(root, arr[i]); } Console.WriteLine(maximumElement(root, a, b)); } } // This code is contributed by Shrikant13 |
Javascript
<script> // JavaScript program to find // maximum element in the path // between two Nodes of Binary // Search Tree. class Node { constructor(val) { this .data = val; this .left = null ; this .right = null ; } } // Create and return a pointer of new Node. function createNode(x) { var p = new Node(); p.data = x; p.left = p.right = null ; return p; } // Insert a new Node in Binary Search Tree. function insertNode(root , x) { var p = root, q = null ; while (p != null ) { q = p; if (p.data < x) p = p.right; else p = p.left; } if (q == null ) p = createNode(x); else { if (q.data < x) q.right = createNode(x); else q.left = createNode(x); } } // Return the maximum element between a Node // and its given ancestor. function maxelpath(q , x) { var p = q; var mx = -1; // Traversing the path between ancestor and // Node and finding maximum element. while (p.data != x) { if (p.data > x) { mx = Math.max(mx, p.data); p = p.left; } else { mx = Math.max(mx, p.data); p = p.right; } } return Math.max(mx, x); } // Return maximum element in the path between // two given Node of BST. function maximumElement(root , x , y) { var p = root; // Finding the LCA of Node x and Node y while ((x < p.data && y < p.data) || (x > p.data && y > p.data)) { // Checking if both the Node lie on the // left side of the parent p. if (x < p.data && y < p.data) p = p.left; // Checking if both the Node lie on the // right side of the parent p. else if (x > p.data && y > p.data) p = p.right; } // Return the maximum of maximum elements occur // in path from ancestor to both Node. return Math.max(maxelpath(p, x), maxelpath(p, y)); } // Driver Code var arr = [ 18, 36, 9, 6, 12, 10, 1, 8 ]; var a = 1, b = 10; var n = arr.length; // Creating the root of Binary Search Tree var root = createNode(arr[0]); // Inserting Nodes in Binary Search Tree for (i = 1; i < n; i++) insertNode(root, arr[i]); document.write(maximumElement(root, a, b)); // This code contributed by gauravrajput1 </script> |
12
Time complexity: O(h), where h is the height of BST
Auxiliary Space: O(1)
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