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Maximum difference between two elements in an Array
• Difficulty Level : Basic
• Last Updated : 04 Apr, 2020

Given an array arr[] of N integers, the task is to find the maximum difference between any two elements of the array.

Examples:

Input: arr[] = {2, 1, 5, 3}
Output: 4
|5 – 1| = 4

Input: arr[] = {-10, 4, -9, -5}
Output: 14

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The maximum absolute difference in the array will always be the absolute difference between the minimum and the maximum element from the array.

Below is the implementation of the above approach:

## C++

 `// C++ implementation of the approach``#include ``using` `namespace` `std;`` ` `// Function to return the maximum``// absolute difference between``// any two elements of the array``int` `maxAbsDiff(``int` `arr[], ``int` `n)``{`` ` `    ``// To store the minimum and the maximum``    ``// elements from the array``    ``int` `minEle = arr;``    ``int` `maxEle = arr;``    ``for` `(``int` `i = 1; i < n; i++) {``        ``minEle = min(minEle, arr[i]);``        ``maxEle = max(maxEle, arr[i]);``    ``}`` ` `    ``return` `(maxEle - minEle);``}`` ` `// Driver code``int` `main()``{``    ``int` `arr[] = { 2, 1, 5, 3 };``    ``int` `n = ``sizeof``(arr) / ``sizeof``(arr);``    ``cout << maxAbsDiff(arr, n);`` ` `    ``return` `0;``}`

## Java

 `// Java implementation of the approach``class` `GFG {`` ` `    ``// Function to return the maximum``    ``// absolute difference between``    ``// any two elements of the array``    ``static` `int` `maxAbsDiff(``int` `arr[], ``int` `n)``    ``{`` ` `        ``// To store the minimum and the maximum``        ``// elements from the array``        ``int` `minEle = arr[``0``];``        ``int` `maxEle = arr[``0``];``        ``for` `(``int` `i = ``1``; i < n; i++) {``            ``minEle = Math.min(minEle, arr[i]);``            ``maxEle = Math.max(maxEle, arr[i]);``        ``}`` ` `        ``return` `(maxEle - minEle);``    ``}`` ` `    ``// Driver code``    ``public` `static` `void` `main(String[] args)``    ``{``        ``int``[] arr = { ``2``, ``1``, ``5``, ``3` `};``        ``int` `n = arr.length;``        ``System.out.print(maxAbsDiff(arr, n));``    ``}``}`

## Python3

 `# Python3 implementation of the approach`` ` `# Function to return the maximum``# absolute difference between``# any two elements of the array``def` `maxAbsDiff(arr, n):`` ` `    ``# To store the minimum and the maximum``    ``# elements from the array``    ``minEle ``=` `arr[``0``]``    ``maxEle ``=` `arr[``0``]``    ``for` `i ``in` `range``(``1``, n):``        ``minEle ``=` `min``(minEle, arr[i])``        ``maxEle ``=` `max``(maxEle, arr[i])`` ` `    ``return` `(maxEle ``-` `minEle)`` ` `# Driver code``arr ``=` `[``2``, ``1``, ``5``, ``3``]``n ``=` `len``(arr)``print``(maxAbsDiff(arr, n))`` ` `# This code is contributed ``# by mohit kumar`

## C#

 `// C# implementation of the approach ``using` `System;`` ` `class` `GFG``{ `` ` `    ``// Function to return the maximum ``    ``// absolute difference between ``    ``// any two elements of the array ``    ``static` `int` `maxAbsDiff(``int` `[]arr, ``int` `n) ``    ``{ `` ` `        ``// To store the minimum and the maximum ``        ``// elements from the array ``        ``int` `minEle = arr; ``        ``int` `maxEle = arr; ``        ``for` `(``int` `i = 1; i < n; i++) ``        ``{ ``            ``minEle = Math.Min(minEle, arr[i]); ``            ``maxEle = Math.Max(maxEle, arr[i]); ``        ``} `` ` `        ``return` `(maxEle - minEle); ``    ``} `` ` `    ``// Driver code ``    ``public` `static` `void` `Main() ``    ``{ ``        ``int``[] arr = { 2, 1, 5, 3 }; ``        ``int` `n = arr.Length; ``         ` `        ``Console.WriteLine(maxAbsDiff(arr, n)); ``    ``} ``} `` ` `// This code is contributed by Ryuga`

## PHP

 `
Output:
```4
```
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