Maximum absolute difference in an array

Given an array arr[] of N integers, the task is to find the maximum absolute difference between any two elements of the array.

Examples:

Input: arr[] = {2, 1, 5, 3}
Output: 4
|5 – 1| = 4



Input: arr[] = {-10, 4, -9, -5}
Output: 14

Approach: The maximum absolute difference in the array will always be the absolute difference between the minimum and the maximum element from the array.

Below is the implementation of the above approach:

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to return the maximum
// absolute difference between
// any two elements of the array
int maxAbsDiff(int arr[], int n)
{
  
    // To store the minimum and the maximum
    // elements from the array
    int minEle = arr[0];
    int maxEle = arr[0];
    for (int i = 1; i < n; i++) {
        minEle = min(minEle, arr[i]);
        maxEle = max(maxEle, arr[i]);
    }
  
    return (maxEle - minEle);
}
  
// Driver code
int main()
{
    int arr[] = { 2, 1, 5, 3 };
    int n = sizeof(arr) / sizeof(arr[0]);
    cout << maxAbsDiff(arr, n);
  
    return 0;
}

chevron_right


Java

filter_none

edit
close

play_arrow

link
brightness_4
code

// Java implementation of the approach
class GFG {
  
    // Function to return the maximum
    // absolute difference between
    // any two elements of the array
    static int maxAbsDiff(int arr[], int n)
    {
  
        // To store the minimum and the maximum
        // elements from the array
        int minEle = arr[0];
        int maxEle = arr[0];
        for (int i = 1; i < n; i++) {
            minEle = Math.min(minEle, arr[i]);
            maxEle = Math.max(maxEle, arr[i]);
        }
  
        return (maxEle - minEle);
    }
  
    // Driver code
    public static void main(String[] args)
    {
        int[] arr = { 2, 1, 5, 3 };
        int n = arr.length;
        System.out.print(maxAbsDiff(arr, n));
    }
}

chevron_right


Python3

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 implementation of the approach
  
# Function to return the maximum
# absolute difference between
# any two elements of the array
def maxAbsDiff(arr, n):
  
    # To store the minimum and the maximum
    # elements from the array
    minEle = arr[0]
    maxEle = arr[0]
    for i in range(1, n):
        minEle = min(minEle, arr[i])
        maxEle = max(maxEle, arr[i])
  
    return (maxEle - minEle)
  
# Driver code
arr = [2, 1, 5, 3]
n = len(arr)
print(maxAbsDiff(arr, n))
  
# This code is contributed 
# by mohit kumar

chevron_right


C#

filter_none

edit
close

play_arrow

link
brightness_4
code

// C# implementation of the approach 
using System;
  
class GFG
  
    // Function to return the maximum 
    // absolute difference between 
    // any two elements of the array 
    static int maxAbsDiff(int []arr, int n) 
    
  
        // To store the minimum and the maximum 
        // elements from the array 
        int minEle = arr[0]; 
        int maxEle = arr[0]; 
        for (int i = 1; i < n; i++) 
        
            minEle = Math.Min(minEle, arr[i]); 
            maxEle = Math.Max(maxEle, arr[i]); 
        
  
        return (maxEle - minEle); 
    
  
    // Driver code 
    public static void Main() 
    
        int[] arr = { 2, 1, 5, 3 }; 
        int n = arr.Length; 
          
        Console.WriteLine(maxAbsDiff(arr, n)); 
    
  
// This code is contributed by Ryuga

chevron_right


PHP

filter_none

edit
close

play_arrow

link
brightness_4
code

<?php
// PHP implementation of the approach
  
// Function to return the maximum
// absolute difference between
// any two elements of the array
function maxAbsDiff($arr, $n)
{
  
    // To store the minimum and the maximum
    // elements from the array
    $minEle = $arr[0];
    $maxEle = $arr[0];
    for ($i = 1; $i < $n; $i++)
    {
        $minEle = min($minEle, $arr[$i]);
        $maxEle = max($maxEle, $arr[$i]);
    }
  
    return ($maxEle - $minEle);
}
  
// Driver code
$arr = array(2, 1, 5, 3);
$n = sizeof($arr);
echo maxAbsDiff($arr, $n);
  
// This code is contributed
// by Akanksha Rai

chevron_right


Output:

4


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.