# Maximize GCD of all possible pairs from 1 to N

Given an integer N (? 2), the task is to find the maximum GCD among all pairs possible by the integers in the range [1, N].

Example:

Input: N = 5
Output:
Explanation :
GCD(1, 2) : 1
GCD(1, 3) : 1
GCD(1, 4) : 1
GCD(1, 5) : 1
GCD(2, 3) : 1
GCD(2, 4) : 2
GCD(2, 5) : 1
GCD(3, 4) : 1
GCD(3, 5) : 1
GCD(4, 5) : 1
Input: N = 6
Output:
Explanation: GCD of pair (3, 6) is the maximum.

Naive Approach:
The simplest approach to solve the problem is to generate all possible pairs from [1, N] and calculate GCD of each pair. Finally, print the maximum GCD obtained.
Time Complexity: O(N2logN)
Auxiliary Space: O(1)
Efficient Approach:
Follow the steps below to solve the problem:

• Since all the pairs are distinct, then, for any pair {a, b} with GCD g, either of a or b is greater than g.
• Considering b to be the greater number, b ? 2g, since 2g is the smallest multiple of g greater than it.
• Since b cannot exceed N, and 2g ? N.
• Therefore, g ? floor(n/2).
• Therefore, the maximum GCD that can be obtained is floor(n/2), when pair chosen is (floor(n/2), 2*floor(n/2)).

Illustration:
N = 6
Maximum GCD = 6/2 = 3, occurs for the pair (3, 6)

Below is the implementation of the above approach:

## C++

 `// C++ Program to implement` `// the approach` `#include ` `using` `namespace` `std;`   `// Function to obtain the maximum` `// gcd of all pairs from 1 to n` `void` `find(``int` `n)` `{` `    ``// Print the answer` `    ``cout << n / 2 << endl;` `}`   `// Driver code` `int` `main()` `{` `    ``int` `n = 5;` `    ``// Function call` `    ``find(n);` `    ``return` `0;` `}`

## Java

 `// Java Program to implement` `// the approach` `class` `GFG{` `  `  `// Function to obtain the maximum` `// gcd of all pairs from 1 to n` `static` `void` `find(``int` `n)` `{` `    ``// Print the answer` `    ``System.out.println(n / ``2``);` `}` ` `  `// Driver code` `public` `static` `void` `main(String[] args)` `{` `    ``int` `n = ``5``;` `    ``// Function call` `    ``find(n);` `}` `}`   `// This code is contributed by Ritik Bansal`

## Python3

 `# Python3 program to implement ` `# the approach `   `# Function to obtain the maximum ` `# gcd of all pairs from 1 to n ` `def` `find(n):`   `    ``# Print the answer ` `    ``print``(n ``/``/` `2``)`   `# Driver Code` `if` `__name__ ``=``=` `'__main__'``:`   `    ``# Given n` `    ``n ``=` `5`   `    ``# Function call` `    ``find(n)`   `# This code is contributed by Shivam Singh`

## C#

 `// C# Program to implement` `// the approach` `using` `System;` `class` `GFG{` `   `  `// Function to obtain the maximum` `// gcd of all pairs from 1 to n` `static` `void` `find(``int` `n)` `{` `    ``// Print the answer` `    ``Console.Write(n / 2);` `}` `  `  `// Driver code` `public` `static` `void` `Main(``string``[] args)` `{` `    ``int` `n = 5;` `    ``// Function call` `    ``find(n);` `}` `}` ` `  `// This code is contributed by rock_cool`

Output:

```2

```

Time Complexity: O(1)
Auxiliary Space: O(1)

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Improved By : bansal_rtk_, rock_cool

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