Math pow() method in Java with Example

The java.lang.Math.pow() is used to calculate a number raise to the power of some other number. This function accepts two parameters and returns the value of first parameter raised to the second parameter. There are some special cases as listed below:

• If the second parameter is positive or negative zero then the result will be 1.0.
• If the second parameter is 1.0 then the result will be same as that of the first parameter.
• If the second parameter is NaN then the result will also be NaN.
• The function java.lang.Math.pow() always returns a double datatype.

Syntax:

public static double pow(double a, double b)
Parameter:
a : this parameter is the base
b : this parameter is the exponent.
Return :
This method returns ab.

Example 1: To show working of java.lang.Math.pow() method. 

Java

// Java program to demonstrate working
// of java.lang.Math.pow() method

import java.lang.Math;

class Gfg {

    // driver code
    public static void main(String args[])
    {
        double a = 30;
        double b = 2;
        System.out.println(Math.pow(a, b));

        a = 3;
        b = 4;
        System.out.println(Math.pow(a, b));

        a = 2.5;
        b = 6.9;
        System.out.println(Math.pow(a, b));
    }
}

Output:

900.0
81.0
556.9113382296638

Time Complexity: O(log(b))

Auxiliary Space: O(1)

Java

// Java program to demonstrate working
// of java.lang.Math.pow() method
import java.lang.Math; // importing java.lang package

public class GFG {
    public static void main(String[] args)
    {

        double nan = Double.NaN;
        double result;

        // Here second argument is NaN,
        // output will be NaN
        result = Math.pow(2, nan);
        System.out.println(result);

        // Here second argument is zero
        result = Math.pow(1254, 0);
        System.out.println(result);

        // Here second argument is one
        result = Math.pow(5, 1);
        System.out.println(result);
    }
}

Output:

NaN
1.0
5.0

Time Complexity: O(log(b))

Auxiliary Space: O(1)