# math.Pow() Function in Golang With Examples

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You can find the base-a exponential of b(a**b)with the help of Pow() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access Pow() function.

Syntax:

`func Pow(a, b float64) float64`
• If Pow(a, ±0), then this method will return 1 for any a.
• If Pow(1, b), then this method will return 1 for any b.
• If Pow(a, 1), then this method will return a for any a.
• If Pow(NaN, b), then this method will return NaN.
• If Pow(a, NaN), then this method will return NaN.
• If Pow(±0, b), then this method will return ± Inf for b an odd integer < 0.
• If Pow(±0, -Inf), then this method will return +Inf.
• If Pow(±0, +Inf), then this method will return +0.
• If Pow(±0, b), then this method will return +Inf for finite b < 0 and not an odd integer.
• If Pow(±0, b), then this method will return ± 0 for b an odd integer > 0.
• If Pow(±0, b), then this method will return +0 for finite b > 0 and not an odd integer.
• If Pow(+1, ±Inf), then this method will return 1.
• If Pow(a, +Inf), then this method will return +Inf for |a| > 1.
• If Pow(a, -Inf), then this method will return +0 for |a| > 1.
• If Pow(a, +Inf), then this method will return +0 for |a| < 1.
• If Pow(a, -Inf), then this method will return +Inf for |a| < 1.
• If Pow(+Inf, b), then this method will return +Inf for b > 0.
• If Pow(+Inf, b), then this method will return +0 for b < 0.
• If Pow(-Inf, b), then this method will return Pow(-0, -b).
• If Pow(a, b), then this method will return NaN for finite a < 0 and finite non-integer b.

Example 1:

 `// Golang program to illustrate ` `// the use of math.Pow() function ` ` `  `package main ` ` `  `import ( ` `    ``"fmt"` `    ``"math"` `) ` ` `  `// Main function ` `func main() { ` ` `  `    ``// Finding the base-a exponential of b ` `    ``// Using Pow() function ` `    ``res_1 := math.Pow(3, 5) ` `    ``res_2 := math.Pow(math.Inf(1), 3) ` `    ``res_3 := math.Pow(2, 0) ` `    ``res_4 := math.Pow(1, math.NaN()) ` `    ``res_5 := math.Pow(-0, math.Inf(-1)) ` ` `  `    ``// Displaying the result ` `    ``fmt.Printf(``"Result 1: %.1f"``, res_1) ` `    ``fmt.Printf(``"\nResult 2: %.1f"``, res_2) ` `    ``fmt.Printf(``"\nResult 3: %.1f"``, res_3) ` `    ``fmt.Printf(``"\nResult 4: %.1f"``, res_4) ` `    ``fmt.Printf(``"\nResult 5: %.1f"``, res_5) ` `} `

Output:

```Result 1: 243.0
Result 2: +Inf
Result 3: 1.0
Result 4: 1.0
Result 5: +Inf
```

Example 2:

 `// Golang program to illustrate ` `// the use of math.Pow() function ` ` `  `package main ` ` `  `import ( ` `    ``"fmt"` `    ``"math"` `) ` ` `  `// Main function ` `func main() { ` `  `  `    ``// Finding the base-a exponential of b ` `    ``// Using Pow() function ` `    ``nvalue_1 := math.Pow(3, 4) ` `    ``nvalue_2 := math.Pow(5, 6) ` ` `  `    ``// Sum of the given numbers ` `    ``res := nvalue_1 + nvalue_2 ` `    ``fmt.Printf(``"%.3f + %.3f = %.3f"``, ` `            ``nvalue_1, nvalue_2, res) ` ` `  `} `

Output:

`81.000 + 15625.000 = 15706.000`

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