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Make A, B and C equal by adding total value N to them

  • Difficulty Level : Basic
  • Last Updated : 12 May, 2021

Given 3 integers A, B, and C, and an integer N, the task is to distribute N among all the other 3 numbers such that at the end A = B = C. If the distribution is possible then print “Yes” otherwise output “No”.
Examples:
 

Input: A = 5, B = 3, C = 2, N = 8 
Output: Yes 
Explanation: 
We can distribute N = 8 by adding 1 to A, 3 to B and 4 to C to get all of them as 6. Hence the distribution is possible.
Input: A = 10, B = 20, C = 15, N = 14 
Output: No 
Explanation: 
Distribution of N among all three integers to make them equal is not possible. 
 

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Approach: 
To solve the problem mentioned above we have to follow the steps given below: 
 

  • Find maximum out of all the three integers A, B and C. Let that be integer K
  • Multiply the integer K by 3 and then subtract it by the sum of the three integers.
  • Check if the difference of that number and N is divisible by 3 or not.
  • If it is, then the output is “Yes”, otherwise it is not possible to distribute the number.

Below is the implementation of the above approach:
 

C++




// C++ program to distribute integer N
// among A, B, C such that they become equal
#include<bits/stdc++.h>
using namespace std;
 
void distributeN(int A, int B, int C, int n)
{
    // Find maximum among the three elements
    int max1 = max(A, B);
    int max2 = max(B, C);
    int maximum = max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3)
        cout << "No";
    else
        cout << "Yes";
}
         
// Driver code
int main()
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
    return 0;
}
 
// This code is contributed by PratikBasu

Java




// Java program to distribute integer N
// among A, B, C such that they become equal
class GFG{
 
static void distributeN(int A, int B, int C,
                        int n)
{
     
    // Find maximum among the three elements
    int max1 = Math.max(A, B);
    int max2 = Math.max(B, C);
    int maximum = Math.max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3 == 0)
        System.out.print("No");
    else
        System.out.print("Yes");
}
         
// Driver code
public static void main(String[] args)
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
}
}
 
// This code is contributed by Rajput-Ji

Python3




# Python3 Program to Distribute integer N
# among A, B, C such that they become equal
 
def distributeN(A, B, C, n):
     
    # find maximum among the three elements
    maximum = max(A, B, C)
     
    # summation of three elements
    sum = A + B+C
     
     
    p = (3 * maximum)-sum
     
    diff = n-p
     
    # check if difference is divisible by 3
    if diff < 0 or diff % 3:
        print "No"
    else:
        print "Yes"
         
         
# Driver code
A = 10
B = 20
C = 15
n = 14
distributeN(A, B, C, n)

C#




// C# program to distribute integer N
// among A, B, C such that they become equal
using System;
 
class GFG{
 
static void distributeN(int A, int B, int C,
                        int n)
{
     
    // Find maximum among the three elements
    int max1 = Math.Max(A, B);
    int max2 = Math.Max(B, C);
    int maximum = Math.Max(max1, max2);
     
    // Summation of three elements
    int sum = A + B + C;
    int p = (3 * maximum) - sum;
    int diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3 == 0)
        Console.Write("No");
    else
        Console.Write("Yes");
}
         
// Driver code
public static void Main(String[] args)
{
    int A = 10, B = 20;
    int C = 15, n = 14;
     
    distributeN(A, B, C, n);
}
}
 
// This code is contributed by Rajput-Ji

Javascript




<script>
 
// JavaScript program to distribute integer N
// among A, B, C such that they become equal
 
function distributeN(A, B, C, n)
{
    // Find maximum among the three elements
    let max1 = Math.max(A, B);
    let max2 = Math.max(B, C);
    let maximum = Math.max(max1, max2);
     
    // Summation of three elements
    let sum = A + B + C;
    let p = (3 * maximum) - sum;
    let diff = n - p;
     
    // Check if difference is divisible by 3
    if (diff < 0 || diff % 3)
        document.write("No");
    else
        document.write("Yes");
}
         
// Driver code
    let A = 10, B = 20;
    let C = 15, n = 14;
     
    distributeN(A, B, C, n);
 
 
// This code is contributed by Surbhi Tyagi.
 
</script>
Output: 
No

 

Time Complexity: O(1)
 




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