# Linked List | Set 2 (Inserting a node)

• Difficulty Level : Easy
• Last Updated : 13 Oct, 2021

We have introduced Linked Lists in the previous post. We also created a simple linked list with 3 nodes and discussed linked list traversal.
All programs discussed in this post consider the following representations of linked list.

## C++

```
class Node
{
public:
int data;
Node *next;
};
// This code is contributed by rathbhupendra

```

## C

```// A linked list node
struct Node
{
int data;
struct Node *next;
};
```

## Java

```// Linked List Class
{

/* Node Class */
class Node
{
int data;
Node next;

// Constructor to create a new node
Node(int d) {data = d; next = null; }
}
}```

## Python

```# Node class
class Node:

# Function to initialize the node object
def __init__(self, data):
self.data = data  # Assign data
self.next = None  # Initialize next as null

# Function to initialize the Linked List object
def __init__(self):
```

## C#

```/* Linked list Node*/
public class Node
{
public int data;
public Node next;
public Node(int d) {data = d; next = null; }
}

```

## Javascript

```<script>

/* Node Class */
class Node {

// Constructor to create a new node
constructor(d) {
this.data = d;
this.next = null;
}
}
// This code is contributed by todaysgaurav
</script>
```

In this post, methods to insert a new node in linked list are discussed. A node can be added in three ways
1) At the front of the linked list
2) After a given node.
3) At the end of the linked list.

## Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

Add a node at the front: (4 steps process)

Following are the 4 steps to add a node at the front.

## C++

```/* Given a reference (pointer to pointer)
to the head of a list and an int,
inserts a new node on the front of the list. */
{
/* 1. allocate node */
Node* new_node = new Node();

/* 2. put in the data */
new_node->data = new_data;

/* 3. Make next of new node as head */

/* 4. move the head to point to the new node */
}

// This code is contributed by rathbhupendra

```

## C

```/* Given a reference (pointer to pointer) to the head of a list
and an int,  inserts a new node on the front of the list. */
void push(struct Node** head_ref, int new_data)
{
/* 1. allocate node */
struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));

/* 2. put in the data  */
new_node->data  = new_data;

/* 3. Make next of new node as head */

/* 4. move the head to point to the new node */
}
```

## Java

```/* This function is in LinkedList class. Inserts a
new Node at front of the list. This method is
defined inside LinkedList class shown above */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}
```

## Python

```# This function is in LinkedList class
# Function to insert a new node at the beginning
def push(self, new_data):

# 1 & 2: Allocate the Node &
#        Put in the data
new_node = Node(new_data)

# 3. Make next of new Node as head

# 4. Move the head to point to new Node
```

## C#

```/* Inserts a new Node at front of the list. */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}

```

## Javascript

```<script>

/* This function is in LinkedList class. Inserts a
new Node at front of the list. This method is
defined inside LinkedList class shown above */

function push(new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
var new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}

// This code contributed by Rajput-Ji

</script>
```

Time complexity of push() is O(1) as it does a constant amount of work.
Add a node after a given node: (5 steps process)
We are given a pointer to a node, and the new node is inserted after the given node.

## C++

```// Given a node prev_node, insert a
// new node after the given
// prev_node
void insertAfter(Node* prev_node, int new_data)
{

// 1. Check if the given prev_node is NULL
if (prev_node == NULL)
{
cout << "The given previous node cannot be NULL";
return;
}

// 2. Allocate new node
Node* new_node = new Node();

// 3. Put in the data
new_node->data = new_data;

// 4. Make next of new node as
// next of prev_node
new_node->next = prev_node->next;

// 5. move the next of prev_node
// as new_node
prev_node->next = new_node;
}

// This code is contributed by anmolgautam818, arkajyotibasak```

## C

```/* Given a node prev_node, insert a new node after the given
prev_node */
void insertAfter(struct Node* prev_node, int new_data)
{
/*1. check if the given prev_node is NULL */
if (prev_node == NULL)
{
printf("the given previous node cannot be NULL");
return;
}

/* 2. allocate new node */
struct Node* new_node =(struct Node*) malloc(sizeof(struct Node));

/* 3. put in the data */
new_node->data = new_data;

/* 4. Make next of new node as next of prev_node */
new_node->next = prev_node->next;

/* 5. move the next of prev_node as new_node */
prev_node->next = new_node;
} ```

## Java

```/* This function is in LinkedList class.
Inserts a new node after the given prev_node. This method is
defined inside LinkedList class shown above */
public void insertAfter(Node prev_node, int new_data)
{
/* 1. Check if the given Node is null */
if (prev_node == null)
{
System.out.println("The given previous node cannot be null");
return;
}

/* 2. Allocate the Node &
3. Put in the data*/
Node new_node = new Node(new_data);

/* 4. Make next of new Node as next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node as new_node */
prev_node.next = new_node;
} ```

## Python

```# This function is in LinkedList class.
# Inserts a new node after the given prev_node. This method is
# defined inside LinkedList class shown above */
def insertAfter(self, prev_node, new_data):

# 1. check if the given prev_node exists
if prev_node is None:
print "The given previous node must inLinkedList."
return

# 2. Create new node &
# 3. Put in the data
new_node = Node(new_data)

# 4. Make next of new Node as next of prev_node
new_node.next = prev_node.next

# 5. make next of prev_node as new_node
prev_node.next = new_node ```

## C#

```/* Inserts a new node after the given prev_node. */
public void insertAfter(Node prev_node,
int new_data)
{
/* 1. Check if the given Node is null */
if (prev_node == null)
{
Console.WriteLine("The given previous node" +
" cannot be null");
return;
}

/* 2 & 3: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 4. Make next of new Node as
next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node
as new_node */
prev_node.next = new_node;
}
```

## Javascript

```<script>

/* This function is in LinkedList class.
Inserts a new node after the given prev_node. This method is
defined inside LinkedList class shown above */
function insertAfter(prev_node , new_data)
{

/* 1. Check if the given Node is null */
if (prev_node == null)
{
document.write("The given previous node cannot be null");
return;
}

/* 2. Allocate the Node &
3. Put in the data*/
var new_node = new Node(new_data);

/* 4. Make next of new Node as next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node as new_node */
prev_node.next = new_node;
}

// This code is contributed by aashish1995

</script>```

Time complexity of insertAfter() is O(1) as it does a constant amount of work.

Add a node at the end: (6 steps process)
The new node is always added after the last node of the given Linked List. For example if the given Linked List is 5->10->15->20->25 and we add an item 30 at the end, then the Linked List becomes 5->10->15->20->25->30.
Since a Linked List is typically represented by the head of it, we have to traverse the list till the end and then change the next to last node to a new node.

Following are the 6 steps to add node at the end.

## C++

```// Given a reference (pointer to pointer) to the head
// of a list and an int, appends a new node at the end
{

// 1. allocate node
Node* new_node = new Node();

// Used in step 5

// 2. Put in the data
new_node->data = new_data;

// 3. This new node is going to be
// the last node, so make next of
// it as NULL
new_node->next = NULL;

// 4. If the Linked List is empty,
// then make the new node as head
{
return;
}

// 5. Else traverse till the last node
while (last->next != NULL)
{
last = last->next;
}

// 6. Change the next of last node
last->next = new_node;
return;
}

// This code is contributed by anmolgautam818, arkajyotibasak```

## C

```/* Given a reference (pointer to pointer) to the head
of a list and an int, appends a new node at the end  */
void append(struct Node** head_ref, int new_data)
{
/* 1. allocate node */
struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));

struct Node *last = *head_ref;  /* used in step 5*/

/* 2. put in the data  */
new_node->data  = new_data;

/* 3. This new node is going to be the last node, so make next
of it as NULL*/
new_node->next = NULL;

/* 4. If the Linked List is empty, then make the new node as head */
{
return;
}

/* 5. Else traverse till the last node */
while (last->next != NULL)
last = last->next;

/* 6. Change the next of last node */
last->next = new_node;
return;
}
```

## Java

```/* Appends a new node at the end.  This method is
defined inside LinkedList class shown above */
public void append(int new_data)
{
/* 1. Allocate the Node &
2. Put in the data
3. Set next as null */
Node new_node = new Node(new_data);

/* 4. If the Linked List is empty, then make the
{
return;
}

/* 4. This new node is going to be the last node, so
make next of it as null */
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}
```

## Python

``` # This function is defined in Linked List class
# Appends a new node at the end.  This method is
#  defined inside LinkedList class shown above */
def append(self, new_data):

# 1. Create a new node
# 2. Put in the data
# 3. Set next as None
new_node = Node(new_data)

# 4. If the Linked List is empty, then make the
return

# 5. Else traverse till the last node
while (last.next):
last = last.next

# 6. Change the next of last node
last.next =  new_node
```

## C#

```/* Appends a new node at the end. This method is
defined inside LinkedList class shown above */
public void append(int new_data)
{
/* 1. Allocate the Node &
2. Put in the data
3. Set next as null */
Node new_node = new Node(new_data);

/* 4. If the Linked List is empty,
then make the new node as head */
{
return;
}

/* 4. This new node is going to be
the last node, so make next of it as null */
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}

```

## Javascript

```<script>

/* Appends a new node at the end.  This method is
defined inside LinkedList class shown above */
function append(new_data)
{
/* 1. Allocate the Node &
2. Put in the data
3. Set next as null */
var new_node = new Node(new_data);

/* 4. If the Linked List is empty, then make the
{
return;
}

/* 4. This new node is going to be the last node, so
make next of it as null */
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}

// This code contributed by aashish1995
</script>

```

Time complexity of append is O(n) where n is the number of nodes in the linked list. Since there is a loop from head to end, the function does O(n) work.
This method can also be optimized to work in O(1) by keeping an extra pointer to the tail of the linked list/

Following is a complete program that uses all of the above methods to create a linked list.

## C++

```// A complete working C++ program to demonstrate
//  all insertion methods on Linked List
#include <bits/stdc++.h>
using namespace std;

class Node
{
public:
int data;
Node *next;
};

/* Given a reference (pointer to pointer)
to the head of a list and an int, inserts
a new node on the front of the list. */
{
/* 1. allocate node */
Node* new_node = new Node();

/* 2. put in the data */
new_node->data = new_data;

/* 3. Make next of new node as head */

/* 4. move the head to point to the new node */
}

/* Given a node prev_node, insert a new node after the given
prev_node */
void insertAfter(Node* prev_node, int new_data)
{
/*1. check if the given prev_node is NULL */
if (prev_node == NULL)
{
cout<<"The given previous node cannot be NULL";
return;
}

/* 2. allocate new node */
Node* new_node = new Node();

/* 3. put in the data */
new_node->data = new_data;

/* 4. Make next of new node as next of prev_node */
new_node->next = prev_node->next;

/* 5. move the next of prev_node as new_node */
prev_node->next = new_node;
}

/* Given a reference (pointer to pointer) to the head
of a list and an int, appends a new node at the end */
{
/* 1. allocate node */
Node* new_node = new Node();

Node *last = *head_ref; /* used in step 5*/

/* 2. put in the data */
new_node->data = new_data;

/* 3. This new node is going to be
the last node, so make next of
it as NULL*/
new_node->next = NULL;

/* 4. If the Linked List is empty,
then make the new node as head */
{
return;
}

/* 5. Else traverse till the last node */
while (last->next != NULL)
{
last = last->next;
}

/* 6. Change the next of last node */
last->next = new_node;
return;
}

// This function prints contents of
void printList(Node *node)
{
while (node != NULL)
{
cout<<" "<<node->data;
node = node->next;
}
}

/* Driver code*/
int main()
{

// Insert 6. So linked list becomes 6->NULL

// Insert 7 at the beginning.
// So linked list becomes 7->6->NULL

// Insert 1 at the beginning.
// So linked list becomes 1->7->6->NULL

// Insert 4 at the end. So

// Insert 8, after 7. So linked
// list becomes 1->7->8->6->4->NULL

return 0;
}

// This code is contributed by rathbhupendra, arkajyotibasak

```

## C

```// A complete working C program to demonstrate all insertion methods
#include <stdio.h>
#include <stdlib.h>

struct Node
{
int data;
struct Node *next;
};

/* Given a reference (pointer to pointer) to the head of a list and
an int, inserts a new node on the front of the list. */
void push(struct Node** head_ref, int new_data)
{
/* 1. allocate node */
struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));

/* 2. put in the data  */
new_node->data  = new_data;

/* 3. Make next of new node as head */

/* 4. move the head to point to the new node */
}

/* Given a node prev_node, insert a new node after the given
prev_node */
void insertAfter(struct Node* prev_node, int new_data)
{
/*1. check if the given prev_node is NULL */
if (prev_node == NULL)
{
printf("the given previous node cannot be NULL");
return;
}

/* 2. allocate new node */
struct Node* new_node =(struct Node*) malloc(sizeof(struct Node));

/* 3. put in the data  */
new_node->data  = new_data;

/* 4. Make next of new node as next of prev_node */
new_node->next = prev_node->next;

/* 5. move the next of prev_node as new_node */
prev_node->next = new_node;
}

/* Given a reference (pointer to pointer) to the head
of a list and an int, appends a new node at the end  */
void append(struct Node** head_ref, int new_data)
{
/* 1. allocate node */
struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));

struct Node *last = *head_ref;  /* used in step 5*/

/* 2. put in the data  */
new_node->data  = new_data;

/* 3. This new node is going to be the last node, so make next of
it as NULL*/
new_node->next = NULL;

/* 4. If the Linked List is empty, then make the new node as head */
{
return;
}

/* 5. Else traverse till the last node */
while (last->next != NULL)
last = last->next;

/* 6. Change the next of last node */
last->next = new_node;
return;
}

void printList(struct Node *node)
{
while (node != NULL)
{
printf(" %d ", node->data);
node = node->next;
}
}

/* Driver program to test above functions*/
int main()
{

// Insert 6.  So linked list becomes 6->NULL

// Insert 7 at the beginning. So linked list becomes 7->6->NULL

// Insert 1 at the beginning. So linked list becomes 1->7->6->NULL

// Insert 4 at the end. So linked list becomes 1->7->6->4->NULL

// Insert 8, after 7. So linked list becomes 1->7->8->6->4->NULL

printf("\n Created Linked list is: ");

return 0;
}
```

## Java

```// A complete working Java program to demonstrate all insertion methods
{

class Node
{
int data;
Node next;
Node(int d) {data = d; next = null; }
}

/* Inserts a new Node at front of the list. */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}

/* Inserts a new node after the given prev_node. */
public void insertAfter(Node prev_node, int new_data)
{
/* 1. Check if the given Node is null */
if (prev_node == null)
{
System.out.println("The given previous node cannot be null");
return;
}

/* 2 & 3: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 4. Make next of new Node as next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node as new_node */
prev_node.next = new_node;
}

/* Appends a new node at the end.  This method is
defined inside LinkedList class shown above */
public void append(int new_data)
{
/* 1. Allocate the Node &
2. Put in the data
3. Set next as null */
Node new_node = new Node(new_data);

/* 4. If the Linked List is empty, then make the
{
return;
}

/* 4. This new node is going to be the last node, so
make next of it as null */
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}

/* This function prints contents of linked list starting from
the given node */
public void printList()
{
while (tnode != null)
{
System.out.print(tnode.data+" ");
tnode = tnode.next;
}
}

/* Driver program to test above functions. Ideally this function
should be in a separate user class.  It is kept here to keep
code compact */
public static void main(String[] args)
{

// Insert 6.  So linked list becomes 6->NUllist
llist.append(6);

// Insert 7 at the beginning. So linked list becomes
// 7->6->NUllist
llist.push(7);

// Insert 1 at the beginning. So linked list becomes
// 1->7->6->NUllist
llist.push(1);

// Insert 4 at the end. So linked list becomes
// 1->7->6->4->NUllist
llist.append(4);

// Insert 8, after 7. So linked list becomes
// 1->7->8->6->4->NUllist

llist.printList();
}
}
// This code is contributed by Rajat Mishra
```

## Python

```# A complete working Python program to demonstrate all
# insertion methods of linked list

# Node class
class Node:

# Function to initialise the node object
def __init__(self, data):
self.data = data  # Assign data
self.next = None  # Initialize next as null

# Linked List class contains a Node object

def __init__(self):

# Functio to insert a new node at the beginning
def push(self, new_data):

# 1 & 2: Allocate the Node &
#        Put in the data
new_node = Node(new_data)

# 3. Make next of new Node as head

# 4. Move the head to point to new Node

# This function is in LinkedList class. Inserts a
# new node after the given prev_node. This method is
# defined inside LinkedList class shown above */
def insertAfter(self, prev_node, new_data):

# 1. check if the given prev_node exists
if prev_node is None:
print "The given previous node must inLinkedList."
return

#  2. create new node &
#      Put in the data
new_node = Node(new_data)

# 4. Make next of new Node as next of prev_node
new_node.next = prev_node.next

# 5. make next of prev_node as new_node
prev_node.next = new_node

# This function is defined in Linked List class
# Appends a new node at the end.  This method is
# defined inside LinkedList class shown above */
def append(self, new_data):

# 1. Create a new node
# 2. Put in the data
# 3. Set next as None
new_node = Node(new_data)

# 4. If the Linked List is empty, then make the
return

# 5. Else traverse till the last node
while (last.next):
last = last.next

# 6. Change the next of last node
last.next =  new_node

# Utility function to print the linked list
def printList(self):
while (temp):
print temp.data,
temp = temp.next

# Code execution starts here
if __name__=='__main__':

# Insert 6.  So linked list becomes 6->None
llist.append(6)

# Insert 7 at the beginning. So linked list becomes 7->6->None
llist.push(7);

# Insert 1 at the beginning. So linked list becomes 1->7->6->None
llist.push(1);

# Insert 4 at the end. So linked list becomes 1->7->6->4->None
llist.append(4)

# Insert 8, after 7. So linked list becomes 1 -> 7-> 8-> 6-> 4-> None

llist.printList()

# This code is contributed by Manikantan Narasimhan
```

## C#

```// A complete working C# program to demonstrate
// all insertion methods on linked list
using System;

class GFG
{

public class Node
{
public int data;
public Node next;
public Node(int d) {data = d; next = null;}
}

/* Inserts a new Node at front of the list. */
public void push(int new_data)
{
/* 1 & 2: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}

/* Inserts a new node after the given prev_node. */
public void insertAfter(Node prev_node, int new_data)
{
/* 1. Check if the given Node is null */
if (prev_node == null)
{
Console.WriteLine("The given previous" +
" node cannot be null");
return;
}

/* 2 & 3: Allocate the Node &
Put in the data*/
Node new_node = new Node(new_data);

/* 4. Make next of new Node as
next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node as new_node */
prev_node.next = new_node;
}

/* Appends a new node at the end. This method is
defined inside LinkedList class shown above */
public void append(int new_data)
{
/* 1. Allocate the Node &
2. Put in the data
3. Set next as null */
Node new_node = new Node(new_data);

/* 4. If the Linked List is empty,
then make the new node as head */
{
return;
}

/* 4. This new node is going to be the last node,
so make next of it as null */
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}

/* This function prints contents of linked list
starting from the given node */
public void printList()
{
while (tnode != null)
{
Console.Write(tnode.data + " ");
tnode = tnode.next;
}
}

// Driver Code
public static void Main(String[] args)
{
GFG llist = new GFG();

// Insert 6. So linked list becomes 6->NUllist
llist.append(6);

// Insert 7 at the beginning.
// So linked list becomes 7->6->NUllist
llist.push(7);

// Insert 1 at the beginning.
// So linked list becomes 1->7->6->NUllist
llist.push(1);

// Insert 4 at the end. So linked list becomes
// 1->7->6->4->NUllist
llist.append(4);

// Insert 8, after 7. So linked list becomes
// 1->7->8->6->4->NUllist

llist.printList();
}
}

// This code is contributed by Rajput-Ji

```

## Javascript

```<script>

// A complete working javascript program
// to demonstrate all insertion methods

class Node {
constructor(val) {
this.data = val;
this.next = null;
}
}

/* Inserts a new Node at front of the list. */
function push(new_data) {
/*
* 1 & 2: Allocate the Node & Put in the data
*/
var new_node = new Node(new_data);

/* 3. Make next of new Node as head */

/* 4. Move the head to point to new Node */
}

/* Inserts a new node after the given prev_node. */
function insertAfter(prev_node , new_data) {
/* 1. Check if the given Node is null */
if (prev_node == null) {
document.write(
"The given previous node cannot be null"
);
return;
}

/*
* 2 & 3: Allocate the Node & Put in the data
*/
var new_node = new Node(new_data);

/* 4. Make next of new Node as next of prev_node */
new_node.next = prev_node.next;

/* 5. make next of prev_node as new_node */
prev_node.next = new_node;
}

/*
* Appends a new node at the end.
This method is defined inside LinkedList class
* shown above
*/
function append(new_data) {
/*
* 1. Allocate the Node & 2.
Put in the data 3. Set next as null
*/
var new_node = new Node(new_data);

/*
* 4. If the Linked List is empty,
then make the new node as head
*/
return;
}

/*
* 4. This new node is going to be the last node,
so make next of it as null
*/
new_node.next = null;

/* 5. Else traverse till the last node */
while (last.next != null)
last = last.next;

/* 6. Change the next of last node */
last.next = new_node;
return;
}

/*
* This function prints contents of linked list
starting from the given node
*/
function printList() {
while (tnode != null) {
document.write(tnode.data + " ");
tnode = tnode.next;
}
}

/*
* Driver program to test above functions.
Ideally this function should be in a
* separate user class. It is kept here
to keep code compact
*/

// Insert 6. So linked list becomes 6->NUllist
append(6);

// Insert 7 at the beginning. So linked list becomes
// 7->6->NUllist
push(7);

// Insert 1 at the beginning. So linked list becomes
// 1->7->6->NUllist
push(1);

// Insert 4 at the end. So linked list becomes
// 1->7->6->4->NUllist
append(4);

// Insert 8, after 7. So linked list becomes
// 1->7->8->6->4->NUllist

printList();

// This code contributed by gauravrajput1

</script>
```

Output:

` Created Linked list is:  1  7  8  6  4`

You may like to try Practice MCQ Questions on Linked List